tinh hop lí
a, \(\frac{2}{5}\)+\(\frac{-1}{6}-\frac{3}{4}-\frac{-2}{3}\)
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\(S=\frac{1}{2}-\frac{2}{3}+\frac{3}{4}-\frac{4}{5}+\frac{5}{6}+\frac{4}{5}-\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\)
\(S=\left(\frac{1}{2}-\frac{1}{2}\right)-\left(\frac{2}{3}-\frac{2}{3}\right)+\left(\frac{3}{4}-\frac{3}{4}\right)-\left(\frac{4}{5}-\frac{4}{5}\right)+\frac{5}{6}\)
\(S=0-0+0-0+\frac{5}{6}\)
\(S=0+\frac{5}{6}\)
\(S=\frac{5}{6}\)
Cẩn thận nha mấy bn, bài này dễ sai dấu lém đó ng kq vẫn đúng
Ủng hộ mk nha ^_^
\(S=\frac{1}{2}-\frac{2}{3}+\frac{3}{4}-\frac{4}{5}+\frac{5}{6}+\frac{4}{5}-\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\)
\(\Rightarrow S=\left(\frac{1}{2}-\frac{1}{2}\right)+\left(\frac{3}{4}-\frac{3}{4}\right)-\left(\frac{4}{5}-\frac{4}{5}\right)-\left(\frac{2}{3}-\frac{2}{3}\right)+\frac{5}{6}\)
\(\Rightarrow S=\frac{5}{6}\)
a, \(\left(\frac{1}{5}-\frac{1}{4}\right)^2=\left(\frac{-1}{20}\right)^2=\frac{1}{400}\)
b, \(\left(\frac{5}{3}+\frac{1}{2}\right):\frac{-13}{5}+1\frac{5}{6}\)
=> \(\frac{13}{6}:\frac{-13}{5}+\frac{11}{6}\)
=> \(\frac{13}{6}.\frac{5}{-13}+\frac{11}{6}\)
=> \(\frac{-5}{6}+\frac{11}{6}=\frac{6}{6}=1\)
c, \(\left(\frac{3}{17}\right)^4.\left(\frac{-17}{6}\right)^4\)
=> \(\left(\frac{3}{17}.\frac{-17}{6}\right)^4=\left(\frac{-1}{2}\right)^4=\frac{1}{16}\)
\(\frac{-5}{7}+\frac{3}{4}+\frac{-1}{5}+\frac{-2}{7}+\frac{1}{4}\)
\(=\left(\frac{-5}{7}+\frac{-2}{7}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)+\frac{-1}{5}\)
\(=-1+1+\frac{-1}{5}\)
\(=-\frac{1}{5}\)
\(\frac{2}{5}+\frac{-1}{6}-\frac{3}{4}-\frac{-2}{3}\)
\(\Leftrightarrow\frac{2}{5}+\frac{-1}{6}+\frac{-3}{4}+\frac{2}{3}\)
\(\Leftrightarrow\frac{48+\left(-20\right)+\left(-90\right)+80}{120}\)
\(\Leftrightarrow\frac{18}{120}=\frac{3}{20}\). > _ <
\(\frac{2}{5}+\left(-\frac{1}{6}-\frac{3}{4}--\frac{2}{3}\right)\)
\(\frac{2}{5}-\left(-\frac{2}{12}-\frac{9}{12}-\frac{-8}{12}\right)\)
\(\frac{2}{5}-\frac{-1}{4}=\frac{8}{20}-\frac{-5}{20}=\frac{3}{20}\)