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(x2-1)2=9
=> x2-1 = 3
x2 = 3+1
x2 = 4
=> x2 = 4 = 22 ( x2=22 )
<=> x = 2
12:{390:[5.102-(53+x.72)]} = 4
390:[5.102-(53+x.72)] = 12:4
390:[5.102-(53+x.72)] = 3
5.102-(53+x.72) = 390 : 3
5.102-(53+x.72) = 130
=> 500-(125+x+49)=130
125+x+49 = 500-130
125+x+49 = 370
125+x = 370-49
125+x = 321
x = 321-125
x = 106
53(3x+2):13=103:(135:134)
53(3x+2):13=103:13
53(3x+2):13= 1000/13
125(3x+2):13 = 1000/13
125(3x+2) = 1000/13 . 13
125(3x+2) = 1000
3x+2 = 1000:125
3x+2 = 8
3x = 8-2
3x = 6
x = 6:3
x = 2
Tìm x, biết:
3(x+2)(x+5) +5(x+5)(x+10) +7(x+10)(x+17) =x(x+2)(x+17) (x∉−2;−5;−10;−17)
2(x−1)(x−3) +5(x−3)(x−8) +12(x−8)(x−20) −1x−20 =−34 (x∉1;3;8;20)
x+110 +2+111 x+112 =x+113 +x+114
x−1030 +x−1443 +x−595 +x−1488 =0
a) 2|x+1|=10
\(\left|x+1\right|\) = 10:2
\(\left|x+1\right|\) = 5
\(\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\) \(\Rightarrow\) \(\left[{}\begin{matrix}x=5-1\\x=\left(-5\right)-1\end{matrix}\right.\) \(\Rightarrow\) \(\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
b) (−12)2x=56+10.13x
144x= 56+130x
144x-130x= 56
14x= 56
x= 56: 14
x= 4
a) 2\(|\)x + 1\(|\) = 10 \(\Rightarrow\) \(|\)x + 1\(|\) = 5
\(\Rightarrow\) x + 1 = 5 hay x = 4
hoặc x + 1 = \(-\)5 hay x = \(-\)6.
ĐS : x = 4, x = \(-\)6.
b) x = 4.
(-12)2.x=56-[-10.13.x]
144.x=56-[-130x]
144x=56+130x
144x-130x=56
14x=56
x=56:14
x=4
Vậy x=4
(-12)2 . x = 56 + 10 . 13 . x
=> 144 . x = 56+130 .x
=> 144x - 130x = 56
=>14x =56
=>4
(-12)2.x=56+10.13.x
=> 144.x=56+130.x
=> 144x-130x=56
=> x(144-130)=56
=> 14x=56
=> x=4
(- 12)\(^2\) . x = 56 - [ (- 10) . 13 . x]
144 . x = 56 - [ -130 . x]
144 . x + (-130) . x = 56
14 . x = 56
x = 56 : 14
x = 4
Vậy x = 4
(-12)2..\(x\) = 56 - [(-10.13.\(x\)]
144\(x\) = 56 + 130\(x\)
144\(x-130x\) = 56
14\(x=56\)
\(x=56:14\)
\(x=4\)
Vậy \(x=4\)