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a) \(3^2.x+2^3.x=51\)
\(\Leftrightarrow x\left(3^2+2^3\right)=51\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=3\)
Vậy
b) \(6^2.2-\left(84-3^2.x\right):7=69\)
\(\Leftrightarrow\left(84-3^2.x\right):7=3\)
\(\Leftrightarrow84-3^2.x=21\)
\(\Leftrightarrow3^2.x=63\)
\(\Leftrightarrow x=7\)
Vậy
\(a,\left(-5\right).\left|x\right|=-75\)
\(\left|x\right|=\frac{-75}{-5}=15\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
Vậy....
\(b,\left(-6\right)^3.x^2=-1944\)
\(-216.x^2=-1944\)
\(x^2=9\)
\(\Rightarrow x=\pm3\)
Vậy....
\(d,\left|9-x\right|=-7+64\)
\(\left|9-x\right|=57\)
\(\Rightarrow\orbr{\begin{cases}9-x=57\\9-x=-57\end{cases}\Rightarrow\orbr{\begin{cases}x=-48\\x=66\end{cases}}}\)
Vậy...
\(e,\left|x+101\right|-\left(-16\right)=\left(-43\right).\left(-5\right)\)
\(\left|x+101\right|+16=215\)
\(\left|x+101\right|=199\)
\(\Rightarrow\orbr{\begin{cases}x+101=199\\x+101=-199\end{cases}\Rightarrow\orbr{\begin{cases}x=98\\x=-300\end{cases}}}\)
Vậy..
hok tốt!!
a,\(\left(-5\right).\left|x\right|=-75\)
\(=>\left|x\right|=-75:\left(-5\right)=15\)
\(=>\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
b,\(\left(-6\right)^3.x^2=-1944\)
\(=>\frac{1944}{216}=x^2\)
\(=>x=\sqrt{\frac{1944}{216}}=3\)
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
Bài 9,
62x73+36x33=36x73+36x27=36(73+27)=36x100=3600.
197-\([\)6x(5-1)2+20220\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.
Bài 10,
21-4x=13
=>4x=21-13=8
=>x=8:4=2.
30:(x-3)+1=45:43=42=16
=>30:(x-3)=16-1=15
=>x-3=30:15=2
=>x=2+3=5.
(x-1)3+5x6=38
=>(x-1)3+30=38
=>(x-1)3=38-30=8=23
=>x-1=2
=>x=3.
`#3107.101107`
`1)`
`58 + 7x = 100`
`=> 7x = 100 - 58`
`=> 7x = 42`
`=> x = 42 \div 7`
`=> x = 6`
Vậy, `x = 6`
`2)`
`(x - 12) \div 12 = 12`
`=> x - 12 = 12*12`
`=> x - 12 = 144`
`=> x = 144 + 12`
`=> x = 156`
Vậy, `x = 156`
`3)`
`x - 56 \div 4 = 16`
`=> x - 14 = 16`
`=> x = 16 + 14`
`=> x = 30`
Vậy, `x = 30`
`4)`
`101 + (36 - 4x) = 105`
`=> 36 - 4x = 105 - 101`
`=> 36 - 4x = 4`
`=> 4x = 36 - 4`
`=> 4x = 32`
`=> x = 32 \div 4`
`=> x = 8`
Vậy, `x = 8`
`5)`
`2(x - 51) = 2*2^3 + 20`
`=> 2(x - 51) = 2^4 + 20`
`=> 2(x - 51) = 16 + 20`
`=> 2(x - 51) = 36`
`=> x - 51 = 36 \div 2`
`=> x - 51 = 18`
`=> x = 18 + 51`
`=> x = 69`
Vậy, `x = 69.`
1) 58 + 7x=100
7x = 100 - 58
7x = 42
x = 42 : 7
x = 6
2)(x-12):12=12
(x - 12) = 12 x 12
x - 12 = 144
x = 144 + 12
x = 156
3)x-56:4=16
x - 14 = 16
x = 16 + 14
x = 30
4) 101+(36-4x)=105
(36-4x) = 105 - 101
36-4x = 4
4x = 36 - 4
4x = 32
x = 32 : 4
x = 8
5)2(x-51)=2.2 mũ 3 + 20
2(x-51)=2.8 + 20
2(x-51)=16 + 20
2(x-51)= 36
x - 51 = 36 : 2
x - 51 = 18
x = 18 + 51
x = 69
a/ \(51-(-12+3x)=27\)
\(\Leftrightarrow51+12-27-3x=0\Leftrightarrow36=3x\Leftrightarrow x=\frac{36}{3}=12\)
KL:........
b/ $-x + 21=15+ 2x$
\(\Leftrightarrow2x+x=21-15\Leftrightarrow2x=6\Leftrightarrow x=3\)
KL: ...........
c) $7.(x-9)-5(6-x)=-6+11.x$
\(\Leftrightarrow7x-63-30+5x=-6+11x\Leftrightarrow7x+5x-11x=-6+63+30\Leftrightarrow x=87\)
KL:............
d) $(x-3).(x^2 + 2)=0$
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x^2+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x\in\varnothing\end{matrix}\right.\)\(\Leftrightarrow x=3\)
e) $|2x-7|-22=-13$
\(\Leftrightarrow\left|2x-7\right|=9\Leftrightarrow\left[{}\begin{matrix}2x-7=9\\2x-7=-9\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-1\end{matrix}\right.\)
KL: ...........
f) $(2x - 1)^3=-125$
\(\Leftrightarrow\left(2x-1\right)^3=\left(-5\right)^3\Leftrightarrow2x-1=-5\Leftrightarrow x=-2\)
KL: ...........
(x-51).32=81
x-51=81:32
X-51=9
X=51+9=60
x+36=-54
X=-54-36
X=-90