Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
18^3 : 9^3 = 5832 : 729 = 8
125^3 : 25^3 = (5^3)^3 : (5^2)^3 = 5^9 : 5^6 = 5^3 = 125
có quy luật hay lắm
\(18^3:9^3=\left(18:9\right)^3=2^3=8\)
\(125^3:25^3=\hept{\begin{cases}\left(5^3\right)^3:\left(5^2\right)^3=5^9:5^6=5^3=125\\\left(5^3\right)^3:\left(5^2\right)^3=\left(5^3:5^2\right)^3=5^3=125\end{cases}}\)chọn cách nào thì tùy bạn
\(\left(10^3+10^4+125^3\right):5^3=\left[10^3+10^3.10+\left(5^2\right)^3\right]:5^3\)
\(=\left(10^3.11+5^6\right):5^3\)
\(=10^3.11:5^3+5^6:5^3\)
\(=\left(10^3:5^3\right).11+5^3\)
\(=2^3.11+5^3\)
\(=88+125=213\)
\(\left(2^{43}+2^4\right):\left(2^{39}+1\right)=\)tương tự mà làm
Ấn vô đây xem người nhận
Universe Size Comparison 3D - YouTube
a) 2^x.2^4=128
=>2^x.2^2=2^7
=>2^x=2^7:2^2
=>2^x=2^5
=>x=5
b)x^15=x
=>x^15-x=0
=>x(x^16-x)=0
=>2 trượng hợp:x=0 và x^16-1=0(x^16-1=0 cx 2 th nha)
b),d),e) như nhau nha!
c) dễ rồi
\(a)2^x\cdot4=128\)
\(\Rightarrow2^x=\frac{128}{4}\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(b)x^{15}=x\)
\(\Rightarrow x^{15}-x=0\)
\(\Rightarrow x(x^{14}-1)=0\)
\(\Rightarrow\hept{\begin{cases}x=0\\x^{14}-1=0\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=0\\x^{14}=1\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=1\end{cases}}\)
\(c)(2x+1)^3=125\)
\(\Rightarrow(2x+1)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=5-1\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4:2=2\)
\(d)(x-5)^4=(x-5)^6\)
\(\Rightarrow(x-5)^6-(x-5)^4=0\)
\(\Rightarrow(x-5)^4\cdot\left[(x-5)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}(x-5)^4=0\\(x-5)^2-1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=6\end{cases}}\)
\(e)(2x-15)^5=(2x-15)^3\)
\(\Rightarrow(2x-15)^5-(2x-15)^3=0\)
\(\Rightarrow(2x-15)^3-\left[(2x-15)^2-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}(2x-15)^3=0\\(2x-15)^2-1=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=\varnothing\\x=8\end{cases}}\)
Chúc bạn hoc tốt :>
1) . \(\dfrac{1}{2}-\left|\dfrac{1}{5}-\dfrac{1}{4}\right|+\left(-\dfrac{1}{3}\right)^2\\ =\dfrac{1}{2}-\left(\dfrac{1}{4}-\dfrac{1}{5}\right)+\dfrac{1}{9}\\ =\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{5}+\dfrac{1}{9}\)
\(=\dfrac{61}{180}\)
2) . \(\dfrac{1}{3}+\dfrac{4}{3}\left(\dfrac{1}{2}-\dfrac{1}{3}\right)+\left(\dfrac{-2}{3}\right)^2\\ =\dfrac{1}{3}+\dfrac{4}{3}\cdot\dfrac{1}{6}+\dfrac{4}{9}\\ =\dfrac{1}{3}+\dfrac{2}{9}+\dfrac{4}{9}\\ =1\)
\(a,\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Leftrightarrow\left(19x+50\right):14=9\)
\(\Leftrightarrow19x+50=126\)
\(\Leftrightarrow19x=76\Leftrightarrow x=4\)
b) x + ( x + 1 ) + ( x + 2 ) + ... + ( x + 30 ) = 1240
x + x + 1 + x + 2 + ... + x + 30 = 1240
( x + x + ... + x ) + ( 1 + 2 + ... + 30 ) = 1240
Số số hạng là : ( 30 - 1 ) : 1 + 1 = 30 ( số )
Tổng là : ( 30 + 1 ) . 30 : 2 = 465
=> 31x + 465 = 1240
=> 31x = 775
=> x = 25
Vậy........
\(a,1^3+2^3=1+8=9\\ b,1^3+2^3+3^3=1+8+27=9+27=36\\ c,1^3+2^3+3^3+4^3=1+8+27+64=9+91=100\\ d,\left(2^{13}+2^5\right):\left(2^{10}+2^2\right)=2^3\left(2^{10}+2^2\right):\left(2^{10}+2^2\right)=2^3=8\)
a) \(1^3+2^3=1+8=9\)
b) \(1^3+2^3+3^3=1+8+27=36\)
c) \(1^3+2^3+3^3+4^3=1+8+27+64=100\)
d) \(\left(2^{13}+2^5\right):\left(2^{10}+2^2\right)=2^3.\left(2^{10}+2^2\right):\left(2^{10}+2^2\right)=2^3=8\)
\(#NqHahh\)