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19 tháng 10 2023

\(\dfrac{-8}{3}+\dfrac{2}{11}-\dfrac{8}{3}:\dfrac{11}{9}\)

\(=\dfrac{-8}{3}+\dfrac{2}{11}+\dfrac{-8}{3}\cdot\dfrac{9}{11}\)

\(=\dfrac{-8}{3}+\dfrac{2}{11}-\dfrac{24}{11}\)

\(=\dfrac{-8}{3}-\dfrac{22}{11}\)

\(=\dfrac{-8}{3}-2\)

\(=\dfrac{-8}{3}-\dfrac{6}{3}\)

\(=-\dfrac{14}{3}\)

19 tháng 10 2023

-8/3 +2/11 -8/3 :11/9
= -88/33 +6/33 -72/33
=-154/33=-14/3

19 tháng 6 2018

8)\(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)

=\(\frac{4}{9}:\left(-\frac{1}{7}\right)+\frac{59}{9}:\left(-\frac{1}{7}\right)\)

=\(\left(\frac{4}{9}+\frac{59}{9}\right).\left(-7\right)\)

=7.(-7)

=-49

26 tháng 7 2018

a. = \(\dfrac{-1}{24}-\left\{\dfrac{1}{4}-\dfrac{-3}{8}\right\}\)

= \(\dfrac{-1}{24}-\left\{\dfrac{1}{4}+\dfrac{3}{8}\right\}\)

= \(\dfrac{-1}{24}-\dfrac{5}{8}\)

= \(\dfrac{-2}{3}\)

b. = \(12\dfrac{7}{88}-3\dfrac{5}{11}\)

= \(8\dfrac{5}{8}\)

c. = \(\dfrac{-28}{9}+\dfrac{-413}{9}\)

= \(-49\)

d. = \(\dfrac{8}{35}:\dfrac{2}{11}+\dfrac{-8}{35}:\dfrac{2}{11}\)

= \(\dfrac{2}{11}:\left(\dfrac{8}{35}+\dfrac{-8}{35}\right)\)

= 0

AH
Akai Haruma
Giáo viên
18 tháng 9 2018

Lời giải:

a)

\(\frac{\frac{2}{3}-\frac{2}{5}+\frac{2}{7}-\frac{2}{9}+\frac{2}{11}}{\frac{8}{3}-\frac{8}{5}+\frac{8}{7}-\frac{8}{9}+\frac{8}{11}}=\frac{2\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{7}-\frac{1}{9}+\frac{1}{11}\right)}{8\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{7}-\frac{1}{9}+\frac{1}{11}\right)}\) \(=\frac{2}{8}=\frac{1}{4}\)

b)

\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)....\left(\frac{1}{50}-1\right)\left(\frac{1}{51}-1\right)\)

\(=\frac{1-2}{2}.\frac{1-3}{3}.\frac{1-4}{4}....\frac{1-50}{50}.\frac{1-51}{2}=\frac{(-1)(-2)(-3)...(-49)(-50)}{2.3.4....50.51}\)

\(=\frac{(-1)^{50}.1.2.3....49.50}{2.3.4...50.51}=\frac{1}{51}\)

17 tháng 12 2017

a,\(3\dfrac{17}{24}+\left(2\dfrac{8}{15}-4\dfrac{8}{15}\right):\left(2\dfrac{11}{30}-\dfrac{11}{30}\right)\)

\(=\dfrac{89}{24}-2:2\)

\(=\dfrac{65}{24}\)

b,\(0,5:\sqrt{625}-\sqrt{\dfrac{4}{25}}+0,18.\left(\sqrt{1\dfrac{9}{16}}-\sqrt{\dfrac{9}{16}}\right)\)

\(=0,5:25-\dfrac{2}{5}+0,18.\dfrac{1}{2}\)

\(=-\dfrac{29}{100}\)

4 tháng 8 2018

Ta có : a, 25/7 + 13/21 - 11/7 + 17/21 + 1/3 .

= ( 25/7 - 11/7 ) + ( 13/21 + 17/21 + 1/3 ) .

= 2 + ( 20/21 + 7/21 ) .

= 2 + 9/7 .

= 23/7 .

b, ( 1/3 + 12/67 + 13/41 ) - ( 79/67 - 28/41 ) .

= 1/3 + 12/67 + 13/41 - 79/67 + 28/41 .

= 1/3 + ( 12/67 - 79/67 ) + ( 13/41 + 28/41 ) .

= 1/3 - 1 + 1 .

= 1/3 .

c, ( 11/4 . -5/9 - 4/9 . 11/4 ) . 8/33 .

= [ 11/4 . ( -5/9 - 4/9 ) ] . 8/33 .

= [ 11/4 . ( - 1 ) ] . 8/33 .

= -11/4 . 8/33 .

= -2/3 .

d, 38/45 - ( 8/45 - 17/51 - 3/11 ) .

= 38/45 - 8/45 + 17/51 + 3/11 .

= 2/3 + 17/51 + 3/11 .

= 374/561 + 187/561 + 153/561 .

= 14/11 .

20 tháng 6 2018

a/Ta có: \(\dfrac{4}{3}-\left[\left(\dfrac{-11}{6}\right)-\left(\dfrac{2}{9}+\dfrac{5}{3}\right)\right]\)

\(=\) \(\dfrac{4}{3}-\left[\dfrac{-11}{6}-\dfrac{2}{9}-\dfrac{5}{3}\right]\)

\(=\) \(\dfrac{4}{3}+\dfrac{11}{6}+\dfrac{2}{9}+\dfrac{5}{3}\)

\(=\) \(\dfrac{24}{18}+\dfrac{33}{18}+\dfrac{4}{18}+\dfrac{30}{18}\)

\(=\) \(\dfrac{91}{18}\)

b/Ta có: \(\left(8-\dfrac{9}{4}+\dfrac{2}{7}\right)-\left(-6-\dfrac{3}{7}+\dfrac{5}{4}\right)-\left(3+\dfrac{2}{4}-\dfrac{9}{7}\right)\)

\(=\) \(8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)

\(=\) \(8+6-3-\dfrac{9}{4}-\dfrac{5}{4}-\dfrac{2}{4}+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}\)

\(=\) \(11-\dfrac{2}{4}+\dfrac{14}{7}\)

\(=\) \(11-\dfrac{1}{2}+2\)

\(=\) \(9-\dfrac{1}{2}\)

\(=\) \(\dfrac{17}{2}\)

Chúc bn học tốt!!!okokok

22 tháng 6 2018

phần b thầy mk chữa là = 9 đó

những dù sao cx thank youvui

4 tháng 8 2018

\(a)\dfrac{-1}{4}.13\dfrac{9}{11}-0,25.6\dfrac{2}{11}\)

\(=\dfrac{-1}{4}.\dfrac{152}{11}-\dfrac{1}{4}.\dfrac{68}{11}\)

\(=-38-\dfrac{17}{11}\)

\(=\dfrac{-418}{11}+\dfrac{-17}{11}\)

\(=\dfrac{-435}{11}\)

\(b)\dfrac{31}{9}.\left|x\right|-\dfrac{5}{2}=\dfrac{8}{3}\)

\(\Leftrightarrow\dfrac{31}{9}.\left|x\right|=\dfrac{16}{6}+\dfrac{15}{6}\)

\(\Leftrightarrow\dfrac{31}{9}.\left|x\right|=\dfrac{31}{6}\)

\(\Leftrightarrow\left|x\right|=\dfrac{31}{6}.\dfrac{9}{31}\)

\(\Leftrightarrow\left|x\right|=1,5\)

\(\Leftrightarrow x\in\left\{1,5;-1,5\right\}\)

Vậy \(x\in\left\{1,5;-1,5\right\}\)

22 tháng 10 2017

\(\dfrac{\dfrac{2}{3}-\dfrac{2}{5}+\dfrac{2}{9}+\dfrac{2}{13}}{\dfrac{11}{3}-\dfrac{11}{5}+\dfrac{11}{9}+\dfrac{11}{13}}\)

\(=\dfrac{2\cdot\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{9}+\dfrac{1}{13}\right)}{11\cdot\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{9}+\dfrac{1}{13}\right)}\)

\(=\dfrac{2}{11}\)

29 tháng 7 2018

A)0,25:(10,3-9,8)-3/4

=1/4:(103/10-49/5)-3/4

=1/4:1/2-3/4

=1/2-3/4

=2/4-3/4

=-1/4

B)-5/9.13/28-13/28.4/9

=-5/9-4/9.13/28

=-1.13/28

=-13/28

c)6/7+5/8:5-3/16

=6/7+1/8-3/16

=55/56-3/16

=89/112

d)-5/7.2/11+-5/7.9/11+1/5/7

=-5/7.(2/11+9/11)+12/7

=-5/7.1+12/7

=-5/7+12/7

=1

e)-7/12-8/15+11/20

=-67/60+11/20

=-17/30

f)-17/25.20/33+-17/25.13/33+-3/25

=-17/25.(20/33+13/33)-3/25

=-17/25.1-3/25

=-17/25-3/25

=-4/5

CHÚC BẠN HỌC TỐT...............

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