Question

[Nguyễn Tuệ Minh]

1 ( x + 8 ) chia hết cho x
2, ( 3x + 16 ) chia hết cho ( x + 4 )

Answer 1

[Nguyễn Đức Trí]

1) \(\left(x+8\right)⋮x\)

\(\Rightarrow x+8-x⋮x\)

\(\Rightarrow8⋮x\)

\(\Rightarrow x\in U\left(8\right)=\left\{-1;1;-2;2;-4;4;-8;8\right\}\left(x\in Z\right)\)

2) \(3x+16⋮x+4\)

\(\Rightarrow3x+16-3\left(x+4\right)⋮x+4\)

\(\Rightarrow3x+16-3x-12⋮x+4\)

\(\Rightarrow4⋮x+4\)

\(\Rightarrow x+4\in U\left(4\right)=\left\{-1;1;-2;2;-4;4\right\}\)

\(\Rightarrow x\in=\left\{-5;-3;-6;-2;-8;0\right\}\left(x\in Z\right)\)

Answer 2

[Lê Thị hoài trang]

Bài này dể mà ko bít lm haizz