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a)\(\frac{-1}{3}.\frac{141}{17}-13.\frac{-1}{17}\)
\(=\frac{141}{3}.\frac{-1}{17}-13.\frac{-1}{17}\)
\(=47.\frac{-1}{17}-13.\frac{-1}{3}\)
\(=\frac{-1}{17}.\left(47-13\right)\)
\(=\frac{-1}{17}.33=....\)(tự tính)
\(a,\)\(\frac{-1}{3}.\frac{141}{17}-13.\frac{-1}{7}\)
\(=\frac{-1.141}{3.17}+13.\frac{1}{17}\)
\(=\frac{-141}{17}.\frac{1}{7}+13.\frac{1}{7}\)
\(=\frac{1}{7}\left(-47+13\right)\)
\(=\frac{-34}{7}\)
\(b,\)\(\frac{-9}{16}.\frac{13}{3}-\left(-\frac{3}{4}\right)^2.\frac{19}{3}\)
\(=\left(\frac{3}{4}\right)^2.\frac{-13}{3}-\left(-\frac{9}{16}\right).\frac{19}{3}\)
\(=\frac{9}{16}.\frac{-13}{3}+\frac{9}{16}.\frac{19}{3}\)
\(=\frac{9}{16}\left(\frac{-13}{3}+\frac{19}{3}\right)=\frac{9}{16}.2=\frac{9}{8}\)
a, 3 . 52 - 27 : 32
= 75 - 3
= 72
b, 24 . 19 - 24 . 16
= 24 . ( 19 - 16 )
= 24 . 3
= 48
c, 15 - 141 + 59 . 15 - 120
= -126 + 885 - 120
= 639
d, 50 - [ 30 - ( 7 - 3 )2 ]
= 50 - [ 30 - 42 ]
= 50 - 14 = 36
`20x-19=141`
`=> 20x=141+19`
`=> 20x= 160`
`=> x= 160:20`
`=>x=8`
Vậy `x=8`
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