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\(\left[\left(\frac{40}{130}-\frac{12}{13}\right)\times40\%+0,15\right]:\frac{-5}{52}\)
\(=\left[\left(\frac{4}{13}-\frac{12}{13}\right)\times\frac{40}{100}+\frac{15}{100}\right]:\frac{-5}{52}\)
\(=\left[\frac{-8}{13}\times\frac{2}{5}+\frac{3}{20}\right]\times\frac{-52}{5}\)
\(=\left[-\frac{16}{65}+\frac{3}{20}\right]\times\frac{-52}{5}=-\frac{5}{52}\times\left(-\frac{52}{5}\right)=1\)
\(\frac{11}{2}-2,4< a< 1,35:0,15\)
=> 3,1 < a < 9
MÀ a thuộc N
=> a \(\in\){ 4 ; 5 ; 6 ; 7 ; 8 }
Vậy a \(\in\){ 4 ; 5 ; 6 ; 7 ; 8 }
Ta có :
11/2 - 12/5 < a < 27/20 . 20/3
3,1 < a < 9
Vì a thuộc N nên :
---> a thuộc { 4 ; 5 ; 6 ; 7 ; 8 }
a) 3/5 x=4/7+1/5; b)(2x-1/2):3=12;
3/5 x=27/35 (2x-1/2)=12x3
x=27/35:3/5 2x-1/2=36
x=9/7 2x=36+1/2
Vay x=9/7 2x=73/2
x=73/2:2
x=73/4
Vay x=73/4
\(\left(\frac{-5}{12}.\frac{4}{21}+\frac{5}{12}.\frac{-17}{21}\right).\left(\frac{-2}{4}\right)\)
\(=\left(\frac{-5}{12}\left(\frac{4}{21}+\frac{17}{21}\right)\right).\left(\frac{-2}{4}\right)\)
\(=\left(\frac{-5}{12}.1\right).\left(\frac{-2}{4}\right)\)
\(=\frac{-5}{12}.\frac{-2}{4}=\frac{5}{24}\)
\(\left(\frac{-5}{12}.\frac{4}{21}+\frac{5}{12}.\frac{-17}{21}\right).\left(-2,4\right)\)
\(=\left[\frac{\left(-5\right)}{12}+\frac{5}{12}\right].\left[\frac{\left(-17\right)}{21}+\frac{4}{21}\right].\left(\frac{-24}{10}\right)\)
\(=0.\frac{\left(-13\right)}{21}.\frac{\left(-12\right)}{5}\)
\(=0\)
a) x-29/6=13/6+10/12 b)15/26+x/13=46/25
x-29/6=3 x/13=46/25-15/26
x =3+29/6 x/13=821/650
x =47/6 x/650=821/650
x=821
c)2,8-x=6/5-3/5 d)24/x:8/3=0,6
2,8-x=2/5 24/x:8/3=3/5
14/5-x=2/5 24/x =3/5.8/3
x=14/5-2/5 24/x =8/5
x=12/5 24/x =24/15
x =15
a, x - 29/6 = 13/6 + 10/12
x - 29/6 = 26/12+10/12
x - 29/6 =3
x = 3 + 29/6
x = 47/6
vậy x = 47/6
\(\text{a)4,38-19+0,62}\)\(=-14\)
\(b.3,45-5,7+8,55=6,3\)
\(c.14,7+\left(-8,4\right)+\left(-4,7\right)=1.6\)
2.
\(a,-2,4-\left(0,54-2,5\right)=-0,44\)
\(b,-25,4-\left(5,54-2,5\right)=-28,44\)
\(c.2,15-\left(-0,6+0,12\right)=2.63\)
Bài 2:
a, 7,2: 2,4.\(x\) = 45
3.\(x\) = 45
\(x\) = 45: 3
\(x\) = 15
b, 9,15.\(x\) + 2,85.\(x\) = 48
\(x\).( 9,15 + 2,85) = 48
12\(x\) = 48
\(x\) = 48: 12
\(x\) = 4
c) (x.3 + 4) : 5 = 8
x.3 + 4 = 8 x 5
x.3 + 4 = 40
x.3 = 40 - 4
x.3 = 36
x = 36 : 3
x = 12
Vì gieo xúc xắc 20 lần và có 6 lần xuất hiện mặt 3 chấm nên ta có phân số: `6/20`.
Từ đó, ta có: \(\dfrac{6}{20}=\dfrac{3}{10}=0,3\).
Vậy `0,3` là xác suất thực nghiệm xuất hiện mặt 3 chấm.
Do đó, ý B là ý đúng.
* \(\dfrac{15}{12}:x=\left(\dfrac{5}{6}-\dfrac{1}{2}\right).\dfrac{5}{4}\)
\(\dfrac{15}{12}:x=\dfrac{1}{3}.\dfrac{5}{4}\)
\(\dfrac{15}{12}:x=\dfrac{5}{12}\)
\(x=\dfrac{15}{12}:\dfrac{5}{12}\)
\(x=3\)
* \(y:0,15=\left(2,8+0,38\right):0,75\)
\(y:0,15=3,18:0,75\)
\(y:15=4,24\)
\(y=4,24.15\)
\(y=63,6\)
\(\dfrac{12}{5}\times0,15+2,4:0,6\)
\(=\dfrac{12}{5}\times\dfrac{3}{20}+\dfrac{12}{5}:\dfrac{3}{5}\)
\(=\dfrac{12}{5}\times\dfrac{3}{20}+\dfrac{12}{5}\times\dfrac{5}{3}\)
\(=\dfrac{12}{5}\times\left(\dfrac{3}{20}+\dfrac{5}{3}\right)=\dfrac{12}{5}\times\dfrac{109}{60}=\dfrac{109}{25}\)
12/5 x 0,15 + 2,4 : 0,6
= 2,4 x 0,15 + 4
= 0,36 + 4
= 4,36