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1.a)x+7=-5-14
x+7=-19
x=-19-7
x=-26
Vậy x=-26
b)3x-4=(-2)3-11
3x-8=-11
3x=-11+8
3x=-3
x=-3:3
X=-1
Vậy x=-1
c)11+(4x-11)=-9-(-15)
11+(4x-11)=-9+15
11+(4x-11)=6
4x-11=6-11
4x=6
x=\(\dfrac{6}{4}\)
Vậy x=\(\dfrac{6}{4}\)
d)\(\left|2x-1\right|=5\)
⇒2x-1=\(\pm5\)
+Nếu 2x-1=5
2x=6
x=6:2
x=3
Vậy x=3
+Nếu 2x-1=-5
2x=-5+1
2x=-4
x=-4:2
x=-2
Vậy xϵ{3;-2}
e)\(\left|x-7\right|+3=25\)
\(\left|x-7\right|=22\)
⇒x-7=\(\pm22\)
+Nếu x-7=22
x=22+7=29
+Nếu x-7=-22
x=-22+7
x=-15
Vậy xϵ{29;-15}
x + 12 =(-5)-x
x + x = -5 - 12
2x = -17
\(x=-\frac{17}{2}\)
x + 5 = 10 - x
x + x = 10 - 5
2x = 5
\(x=\frac{5}{2}\)
12-x=x+1
12 - 1 = x+x
11=2x
x=\(\frac{11}{2}\)
14+4x=3x-20
4x-3x=-20-14
x=-34
Giải:
a) \(4\left(x+1\right)-\left(3x+1\right)=14\)
\(\Leftrightarrow4x+4-3x-1=14\)
\(\Leftrightarrow x+3=14\)
\(\Leftrightarrow x=14-3=11\)
Vậy ...
b) \(-2\left(x-1\right)-\left(2-3x\right)=2\left(x+1\right)-4\)
\(\Leftrightarrow-2x+2-2+3x=2x+2-4\)
\(\Leftrightarrow x=2x-2\)
\(\Leftrightarrow x-2x=-2\)
\(\Leftrightarrow-x=-2\)
\(\Leftrightarrow x=2\)
Vậy ...
c) \(-\left(x-3\right)+\left(4x-1\right)-14=2\left(x-2\right)-5\)
\(\Leftrightarrow-x+3+4x-1-14=2x-4-5\)
\(\Leftrightarrow3x-15=2x-9\)
\(\Leftrightarrow3x-2x=-9+15\)
\(\Leftrightarrow x=6\)
Vậy ...
a) \(3x⋮x-2\)
ta có \(x-2⋮x-2\)
\(\Rightarrow3\left(x-2\right)⋮x-2\)
\(\Rightarrow3x-6⋮x-2\)
mà \(3x⋮x-2\)
\(\Rightarrow3x-\left(3x-6\right)⋮x-2\)
\(\Rightarrow3x-3x+6\) \(⋮x-2\)
\(\Rightarrow6\) \(⋮x-2\)
\(\Rightarrow x-2\in\text{Ư}_{\left(6\right)}=\text{ }\left\{1;2;3;6\right\}\)
+) nếu \(x-2=1\Rightarrow x=3\) ( thỏa mãn )
+) nếu \(x-2=2\Rightarrow x=4\) ( thỏa mãn )
+) nếu \(x-2=3\Rightarrow x=5\) ( thỏa mãn )
+) nếu \(x-2=6\Rightarrow x=8\) ( thỏa mãn )
vậy \(x\in\text{ }\left\{3;4;5;8\right\}\)
2(2x-1)-3(5-4x)=1=1+4(x-2)
=>1=1+4(x-2)
=>4(x-2)=0
=>x-2=0
=>x=2
2(2x-1)-3(5-4x)=1=1+4(x-2)
=>1=1+4(x-2)
=>4(x-2)=0
=>x-2=0
=>x=2
a: \(\Leftrightarrow x^2-x+4x-4+5⋮x-1\)
\(\Leftrightarrow x-1\in\left\{1;-1;5;-5\right\}\)
hay \(x\in\left\{2;0;6;-4\right\}\)
c: \(\Leftrightarrow4x-5=13k\left(k\in Z\right)\)
=>4k=13k+5
hay \(x=\dfrac{13k+5}{4}\)
=>8x-4x2+3x2-15x=14
=>x2-7x=14
=>x(x-7)=14
+ x=14
+x-7=14 =>x=21
vậy pt có 2 nghiệm là x=14 và x=21
cho mình nhé bạn