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a) \(x-\frac{4}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{4}{5}=\frac{53}{35}\)
b) \(5x=-\frac{1}{5}\)
\(x=-\frac{1}{5}:5=-\frac{1}{25}\)
c) \(\frac{5}{3}-x=7+\frac{4}{5}\)
\(\frac{5}{3}-x=\frac{39}{5}\)
\(x=\frac{5}{3}-\frac{39}{5}=-\frac{92}{15}\)
d) \(-\frac{5}{11}+2x=\frac{7}{22}\)
\(2x=\frac{7}{22}+\frac{5}{11}\)
\(2x=\frac{17}{22}\)
\(x=\frac{17}{22}:2\)
\(x=\frac{17}{44}\)
\(x=-\frac{1}{5}:5\)
NÈ BẠN!!!
a) \(x-\frac{4}{5}=\frac{5}{7}\)
\(x=\frac{5}{7}+\frac{4}{5}=\frac{25}{35}+\frac{28}{35}=\frac{53}{35}\)
b) \(5x=-\frac{1}{5}+\frac{11}{5}\)
\(5x=2\)
\(x=\frac{2}{5}\)
c)\(\frac{5}{3}-x=7\)
\(x=\frac{5}{3}-7=\frac{5}{3}-\frac{21}{3}=-\frac{16}{3}\)
d) \(-\frac{5}{11}+2x=\frac{7}{22}\)
\(2x=\frac{7}{22}-\frac{-5}{11}=\frac{7}{22}-\frac{-10}{22}=\frac{17}{22}\)
\(x=\frac{17}{22}:2=\frac{17}{22}\cdot\frac{1}{2}=\frac{17}{44}\)
K CHO MÌNH NHA!!!
Câu 1 :
\(x:\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{101.103}\right)=1\)
\(=>x:\left[\frac{1}{2}.\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{101}-\frac{1}{103}\right)\right]\) \(=1\)
\(=>x:\left[\frac{1}{2}.\left(\frac{1}{1}-\frac{1}{103}\right)\right]=1\)
\(=>\) \(x:\frac{51}{103}=1\)
\(=>x=1.\frac{51}{103}=\frac{51}{103}\)
Câu 2 :
\(\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{12.13}\right).x=2\)
\(=>\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}\right).x=2\)
\(=>\left(\frac{1}{1}-\frac{1}{12}\right).x=2\)
\(=>\frac{11}{12}.x=2\)
\(=>x=2:\frac{11}{12}\)
\(=>x=\frac{24}{11}\)
3/(x-5) = -4/(x+2)
=> 3(x + 2) = -4(x - 5)
=> 3x + 6 = -4x + 20
=> 3x + 4x = 20 - 6
=> 7x = 14
=> x = 2
Câu hỏi của Bé Lựu Cute - Toán lớp 6 - Học toán với OnlineMath
a) \(3x-\frac{3}{2}-5x+\frac{10}{3}=1\)
\(3x-5x=1+\frac{3}{2}-\frac{10}{3}\)
\(-2x=-\frac{5}{6}\)
\(x=\frac{5}{12}\)
b) \(\left|x-1\right|=5-x\)
Th1:
\(x-1=5-x\)
\(x+x=5+1\)
\(2x=6\)
\(x=3\)
Th2:
\(-\left(x-1\right)=5-x\)
\(x+1=5-x\)
\(x+x=5-1\)
\(2x=4\)
\(x=2\)
Vậy \(x=3\)và \(x=2\)
a) 3x - 5x = 1 + 3/2 - 10/3
-2x = -5/6
x = -5/6 : ( - 2 )
x = 5/12
b) |x-1|= 5-x
Nếu x \(\ge\)1 \(\Rightarrow\)x - 1 \(\ge\)0 \(\Rightarrow\)x - 1 = 5 - x.
2x = 6
x = 3.
Nếu x < 1 \(\Rightarrow\)x - 1 < 0 \(\Rightarrow\)Ix-1I = 1 - x
\(\Rightarrow\)1 - x = 5 - x \(\Rightarrow\)vô lý.
Vậy x = 3
\(\Rightarrow\left(\frac{13}{21}+x\right).\frac{7}{12}=\frac{13}{15}-\frac{7}{10}\)
\(\Rightarrow\left(\frac{13}{21}+x\right).\frac{7}{12}=\frac{1}{6}\)
\(\Rightarrow\frac{13}{21}+x=\frac{1}{6}.\frac{12}{7}=\frac{2}{7}\)
\(\Rightarrow x=\frac{2}{7}-\frac{13}{21}=\frac{-1}{3}\)
\(x-40\%x=3,6\)
\(\Rightarrow100\%x-40\%x=3,6\)
\(\Rightarrow60\%x=3,6\)
\(\Rightarrow\frac{60}{100}x=3,6\)
\(\Rightarrow x=6\)
\(3\frac{2}{7}x-\frac{1}{3}=-2\frac{3}{4}\)
\(\Rightarrow\frac{23}{7}x-\frac{1}{3}=-\frac{11}{4}\)
\(\Rightarrow\frac{23}{7}x=-\frac{33}{12}+\frac{4}{12}\)
\(\Rightarrow\frac{23}{7}x=\frac{29}{12}\)
\(\Rightarrow x=\frac{29}{12}:\frac{23}{7}=\frac{203}{276}\)
e,
\(2^x-15=17\\ 2^x=17+15\\ 2^x=32\\ 2^x=2^5\\ x=5\)
Vậy \(x=5\)
d,
\(\left(x-1\right)^5-\left(x-1\right)^2=0\\ \left(x-1\right)^2\cdot\left[\left(x-1\right)^3-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-1\right)^2=0\\\left(x-1\right)^3-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^3=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\\left(x-1\right)^3=1^3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
Vậy \(x=1\) hoặc \(x=2\)
mấy câu còn lại coi lại đề
PT <=> \(\frac{4x}{3}=\frac{14x}{3}+5\)
<=> \(\frac{10x}{3}=-5\)
<=> x= \(-5:\frac{10}{3}=-\frac{15}{10}=-\frac{3}{2}\)
vậy x= - 3/2