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\(\text{CuO+2HCl(dung dịch pha loãng)=CuCl2+H2O}\)
\(\text{Ca(OH)2+CuCl2→Cu(OH)2↓+CaCl2}\)
\(\text{Cu(OH)2 → CuO + H2O}\)
\(\text{CuO + H2SO4 → H2O + CuSO4}\)
\(\text{CuSO4(dung dịch pha loãng)+H2=Cu↓+H2SO4}\)
PT cuối sai
\(CuO+2HCl->CuCl_2+H_2O\)
\(CuCl_2+2NaOH->Cu\left(OH\right)_2+2NaCl\)
\(Cu\left(OH\right)_2->CuO+H_2O\) (Nhiệt độ nữa nha bạn)
\(CuO+H_2SO_4->CuSO_4+H_2O\)
\(CuSO_4\:+Fe->FeSO_4+Cu\)
\(Cu+2AgNO_3->Cu\left(NO_3\right)_2+2Ag\)
a.
2Al2O3 \(\underrightarrow{t^o}\)4Al + 3O2\(\uparrow\)
Al + 6HNO3 \(\rightarrow\) Al(NO3)3\(\downarrow\) + 3NO2 + 3H2O
Al(NO3)3 + NaOH \(\rightarrow\) Al(OH)3\(\downarrow\) + NaNO3
2Al(OH)3 \(\xrightarrow[criolit]{đpnc}\) Al2O3 + 3H2O
Al2O3 + 3H2SO4 \(\rightarrow\) Al2(SO4)3 + 3H2O
Al2(SO4)3 + 3BaCl2 \(\rightarrow\) 3BaSO4\(\downarrow\) + 2AlCl3
2AlCl3 \(\xrightarrow[criolit]{đpnc}\) 2Al + 3Cl2\(\uparrow\)
2Al + 3CuSO4 \(\rightarrow\) 3Cu + Al2(SO4)3
a.
\(H_2SO_4+CuO\rightarrow CuSO_4+H_2O\)
\(Cu\left(OH\right)_2\rightarrow CuO+H_2O\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+2AgNO_3\rightarrow2AgCl+Cu\left(NO_3\right)_2\)
\(Cu\left(NO_3\right)_2+Mg\rightarrow Mg\left(NO_3\right)_2+Cu\)
b.
\(Ca+H_2O\rightarrow Ca\left(OH\right)_2+H_2\)
\(Ca\left(OH\right)_2+FeCl_2\rightarrow Fe\left(OH\right)_2+CaCl_2\)
\(CaCl_2+Na_2CO_3\rightarrow CaCO_3+2NaCl\)
\(2NaCl+2H_2O\underrightarrow{^{đpdd}}2NaOH+Cl_2+H_2\)
\(NaOH+SO_3\rightarrow NaHSO_4\)
c.
\(4Na+O_2\underrightarrow{^{to}}2Na_2O\)
\(Na_2O+2HCl\rightarrow2NaCl+H_2O\)
\(2NaCl+2H_2O\underrightarrow{^{đpdd}}2NaOH+Cl_2+H_2\)
\(2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\)
\(Na_2SO_3+2HCl\rightarrow2NaCl+SO_2+H_2O\)
A/
Cu(OH)2 => (to) CuO + H2O
CuO + H2 => (to) Cu + H2O
Cu +Cl2 => CuCl2
A/
Cu(OH)2\(\xrightarrow[]{to}\) CuO+ H2O
CuO+ H2\(\xrightarrow[]{to}\) Cu+ H2O
Cu+ 2FeCl3\(\rightarrow\) 2FeCl2+ CuCl2
B/
CuO+ CO\(\xrightarrow[]{to}\) Cu+ CO2
Cu+ \(\frac{1}{2}\)O2+ H2O\(\rightarrow\) Cu(OH)2
Cu(OH)2+ 2HCl\(\rightarrow\) CuCl2+ 2H2O
C/
CuO+ C2H5OH\(\rightarrow\) CH3CHO+ Cu(OH)2\(\downarrow\)+ H2O
Cu(OH)2+ 2HCl\(\rightarrow\) CuCl2+ 2H2O
CuCl2+ Fe\(\rightarrow\) FeCl2+ Cu
D/
2Cu+ O2\(\xrightarrow[]{to}\) 2CuO
CuO+ C2H5OH\(\rightarrow\) CH3CHO+ Cu(OH)2\(\downarrow\)+ H2O
Cu(OH)2+ 2HCl\(\rightarrow\) CuCl2+ 2H2O
a)
4Al + 3O2\(\rightarrow\) 2Al2O3
Al2O3 +6HNO3\(\rightarrow\) 2Al(NO3)3 + 3H2O
Al(NO3)3 + 3NaOH \(\rightarrow\)Al(OH)3 + 3NaNO3
2Al(OH)3 \(\underrightarrow{^{to}}\) Al2O3 + 3H2O
Al2O3 +6HCl \(\rightarrow\) 2AlCl3 + 3H2O
AlCl3 không điện phân nóng chảy được \(\rightarrow\) Al2O3 \(\underrightarrow{^{\text{đpnc}}}\)2Al + \(\frac{3}{2}\)O2
b) 2Fe + 3Cl2 \(\rightarrow\) 2FeCl3
FeCl3 + 3NaOH \(\rightarrow\)Fe(OH)3 + 3NaCl
2Fe(OH)3\(\rightarrow\)Fe2O3 + 3H2O
Fe2O3 + 3CO \(\rightarrow\)2Fe + 3CO2
Fe + 2HCl\(\rightarrow\) FeCl2 + 2
FeCl2 + 2AgNO3\(\rightarrow\)Fe(NO3)2 + 2AgCl (thường ra Fe+3 )
c) 2Mg + O2\(\rightarrow\)2MgO
MgO + 2HCl \(\rightarrow\) MgCl2 + H2O
MgCl2 + 2NaOH \(\rightarrow\) Mg(OH)2 + 2NaCl
Mg(OH)2 + H2SO4 \(\rightarrow\)MgSO4 + 2H2O
MgSO4 + BaCl2 \(\rightarrow\) MgCl2 + BaSO4
d) Cu(OH)2\(\underrightarrow{^{to}}\) CuO + H2O
CuO + H2SO4\(\rightarrow\)CuSo4 + H2O
CuSO4 + BaCl2 \(\rightarrow\) BaSO4 + CuCl2
CuCl2 + 2AgNO3 \(\rightarrow\) Cu(NO3)2 + 2AgCl
Fe + Cu(NO3)2\(\rightarrow\) Fe(NO3)2 + Cu
Cu + \(\frac{1}{2}\)O2 \(\rightarrow\) CuO
e) 4Na + O2\(\rightarrow\) 2Na2O
Na2O + H2O \(\rightarrow\) 2NaOH
2NaOH + CO2 \(\rightarrow\)Na2CO3 + H2O
Na2CO3 + H2SO4\(\rightarrow\) Na2SO4 + CO2 + H2O
Na2SO4 + BaCl2 \(\rightarrow\)BaSO4 + 2NaCl
NaCl + AgNO3\(\rightarrow\) AgCl + NaNO3
f) Fe3O4 + 4CO\(\rightarrow\) 3Fe + 4CO2
2Fe + 3Cl2 \(\rightarrow\)2FeCl3
FeCl3 + 3AgNO3 \(\rightarrow\) Fe(NO3)3 +3AgCl
Fe(NO3)3 + 3NaOH \(\rightarrow\) Fe(OH)3 + 3NaNO3
Lần sau đăng tách riêng ra nhé
Nhìn rối mắt lắm
a) Al -> Al2O3-> Al(NO3)3-> Al(OH)3 -> Al2O3 -> AlCl3 -> Al
(1) 2A1 + O2 t0→ Al2O3
(2) Al2O3 + 6HCl → 2AlCl3 + 3H2O
(3) Al(NO3)3 + 3NaOH (vừa đủ) → 3NaNO3 + Al (OH)3
(4) 2Al(OH)3 →t0 Al2O3+ ЗН2О
(5) 2Al2O3 đpnc−−→đpnc 4Al + 3O2
(6) 2Al + 3Cl2 t→t0 2AlCl3
b) Fe -> FeCl3 -> Fe(OH)3 -> Fe2O3-> Fe -> FeCl2 -> Fe(NO3)3
(1) 2Fe + 3Cl2 → 2FeCl3
(2) FeCl3 + 3NaOH → 3NaCl + Fe(OH)3
(3) 2Fe(OH)3 → Fe2O3 + 3H2O
(4) Fe2O3 + H2→ Fe + H2O
(5) 3Fe + 2HCl → 2FeCl2 +H2↑
(6) Fe(NO3)3+3NaOH ➞Fe(OH)3 +3Na(NO3)
dài wá mình trả lời những câu còn lại sau : thông cảm cho mk nha❗❕
PTHH:
Cu + H2SO4 → H2 + CuSO4
CuSO4 + BaCl2 → BaSO4 + CuCl2
CuCl2 + Ba(OH)2 → BaCl2 + Cu(OH)2
Cu(OH)2 \(\underrightarrow{t^0}\) H2O + CuO
2CuO \(\underrightarrow{t^0}\) 2Cu + O2
Cu + H2SO4(ĐẶC NÓNG) -\(t^O\)> CuSO4 + 2H2O + SO2
CuSO4 + BACL2 -> CuCL2 + BASO4
CuCL2 + Pb(OH)2 -> Cu(OH)2 + PbCL2
Cu(OH)2 -\(t^O\)> CuO + H2O
CuO + H2 -\(t^O\)> Cu + H2O
1/ Cao + H2O------> Ca (OH)2
2/ Ca (OH)2 + Fe(NO3)2 -----> Ca (NO3)2+Fe(OH)2
3/ Ca(NO3)2 + H2SO4---> CaSO4+2HNO3
4/ CuCl2 + 2NaOH -----> Cu(OH)2+2NaCl
5/ Cu(OH)2 + Na2SO4-----> CuSO4+2NaOH
6/ CuSO4 +Ba(NO3)2 ------> Cu (NO3)2+BaSO4
7/ CuO +2HCl----> CuCl2+H2O
1. CaO + H2O = Ca(OH)2
2. Ca(OH)2 + 2HNO3 = Ca(NO3)2 + 2H2O
3. Không xảy ra pứ này
4. CuCl2 +2NaOH = 2NaCl + Cu(OH)2
5. Cu(OH)2 + H2SO4 = CuSO4 + 2H2O
6. CuSO4 + Ba(NO3)2 = Cu(NO3)2 + BaSO4
7. CuO + 2HCl = CuCl2 +H2O
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Bài của Duong Le
Thứ nhất: pt số 3 sẽ k xảy ra pứ
Thứ hai: pt số 5 sai
\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\\ CuSO_4+Ba\left(NO_3\right)_2\rightarrow BaSO_4+Cu\left(NO_3\right)_2\\ Cu\left(NO_3\right)_2+2KOH\rightarrow Cu\left(OH\right)_2+2KNO_3\\ Cu\left(OH\right)_2\rightarrow\left(t^o\right)CuO+H_2O\\ CuO+2HCl\rightarrow CuCl_2+H_2O\\ CuCl_2\rightarrow\left(t^o\right)Cu+Cl_2\)