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\(2013=2.1000+10+3=2.10^3+1.10^1+3.10^0\)
\(20112013=2.10000000+100000+10000+2.1000+10+3\)
\(=2.10^7+10^5+10^4+2.10^3+10^1+3.10^0\)
2013 = 2 x 1000 + 10 + 3 = 2 x 10^3 + 1 . 10^1 + 3 . 10^0
20112013 = 2 x 10000000 + 100000 + 2 x 1000 + 10 + 3 = 2 x 10^7 + 10^5 + 10^4 + 2 x 10^3 + 10^1 + 3 x 10^0
ok nhé với lại 10^2 là 10 mũ 2 nhé =>
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`@` `\text {Ans}`
`\downarrow`
`a)`
`16^3 = (4^2)^3 = 4^6`
`b)`
`25^6 = (5^2)^6 = 5^12`
`c)`
`81^5 = (9^2)^5 = 9^10`
`d)`
`27^5 = (3^3)^5 = 3^15`
`e)`
`64^3*16^3`
`= (4^3)^3*(4^2)^3`
`= 4^9*4^6`
`= 4^15`
_____
`@` Nâng lên lũy thừa
CT: `(a^m)^n=a^m*a^n = a^(m*n)`
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a) a b c = a . 100 + b . 100 + c . 1 = a . 10 2 + b . 10 1 + c . 10 0
b) a b c d ¯ = a . 1000 + b . 100 + c . 10 + d = a . 10 3 + b . 10 2 + c . 10 1 + d . 10 0
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a) 538 = 5 . 100 + 3 . 10 + 8 . 1 = 5 . 10 2 + 3 . 10 1 + 8 . 10 0 .
b) 8609 = 8 . 1000 + 6 . 100 + 9 . 1 = 8 . 10 3 + 6 . 10 2 + 9 . 10 0 .
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a) 1 . 10 2 + 2 . 10 1 + 6 . 10 0
b) 1 . 10 4 + 6 . 10 2 + 8 . 10 0
a)\(175=10^2\)\(+10^1\)\(\times7\)\(+10^0\)\(\times5\)
b,\(1893=10^3+8\times10^2+9\times10^1+3\times10^0\)