Question

[Quan Bai Bi An]

• rut gon

             \(\frac{11.12+22.24+44.48}{33.36+66.72+132.144}\) 

Answer 1

[Rinne Tsujikubo]

ta co:

     \(\frac{11.12+22.24+44.48}{33.36+66.72+132.144}\)

   \(=\frac{11.12+11.2.12.2+11.4.12.4}{33.36+33.2.36.2+33.4.36.4}\)

   \(=\frac{11.12.\left(1+2.2+4.4\right)}{33.36.\left(1+2.2+4.4\right)}\)

   \(=\frac{11.12}{36.33}\)

   \(=\frac{1}{3.3}\)

\(=\frac{1}{9}\)