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\(n_{H^+}=0,1.2.0,2=0,04\Rightarrow\left[H^+\right]=\dfrac{0,04}{0,2+0,1}\approx0,13M\)
\(n_{SO_4^{2-}}=0,2.0,1+0,3.0,1=0,05\Rightarrow\left[SO_4^{2-}\right]=\dfrac{0,05}{0,2+0,1}\approx0,17M\)
\(n_{Na^+}=0,3.0,1.2=0,06\Rightarrow\left[Na^+\right]=\dfrac{0,06}{0,2+0,1}\approx0,2M\)
\(n_{NaOH}=0.1\cdot0.4=0.04\left(mol\right)\)
\(n_{Ba\left(OH\right)_2}=0.1\cdot0.4=0.04\left(mol\right)\)
\(\Rightarrow n_{OH^-}=0.04+0.04\cdot2=0.12\left(mol\right)\)
\(V=0.1+0.1=0.2\left(l\right)\)
\(\left[OH^-\right]=\dfrac{0.12}{0.2}=0.6\left(M\right)\)
\(n_{KOH}=0.1\cdot1=0.1\left(mol\right)\)
\(n_{HCl}=0.1\cdot0.5=0.05\left(mol\right)\)
\(KOH+HCl\rightarrow KCl+H_2O\)
\(0.05.......0.05.......0.05\)
Dung dịch D : 0.05 (mol) KOH , 0.05 (mol) KCl
\(\left[K^+\right]=\dfrac{0.05+0.05}{0.1+0.1}=0.5\left(M\right)\)
\(\left[Cl^-\right]=\dfrac{0.05}{0.2}=0.25\left(M\right)\)
\(\left[OH^-\right]=\dfrac{0.05}{0.2}=0.25\left(M\right)\)
\(2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O\)
\(0.05.........0.025\)
\(V_{dd_{H_2SO_4}}=\dfrac{0.025}{1}=0.025\left(l\right)\)
\(n_{HCl}=0,1.0,1=0,01\left(mol\right);n_{HCl}=0,3.0,04=0,012\left(mol\right)\)
Dung dịch gồm H+ và Cl-
\(n_{H^+}=0,01+0,012=0,022\left(mol\right)\)
=> \(\left[H^+\right]=\dfrac{0,022}{0,4}=0,055M\)
\(n_{Cl^-}=0,01+0,012=0,022\left(mol\right)\)
=>\(\left[Cl^-\right]=\dfrac{0,022}{0,4}=0,055M\)
Trộn 100ml dung dịch HNO3 0.1M với 400ml dung dịch H2SO4 0.03M
\(n_{HNO_3}=0,1.0,1=0,01\left(mol\right);n_{H_2SO_4}=0,04.0,3=0,012\left(mol\right)\)
Dung dịch sau khi trộn gồm :
\(n_{H^+}=0,01+0,012.2=0,034\left(mol\right)\)
=> \(\left[H^+\right]=\dfrac{0,034}{0,5}=0,068M\)
\(n_{NO_3^-}=0,01\left(mol\right)\)
=>\(\left[NO_3^-\right]=\dfrac{0,01}{0,5}=0,02M\)
\(n_{SO_4^{2-}}=0,012\left(mol\right)\)
=> \(\left[SO_4^{2-}\right]=\dfrac{0,012}{0,5}=0,024M\)
[K+]=[Cl-]=0,25M
[KOH dư]=0,25M
b) 2KCl + H2SO4 ----------->K2SO4 + 2HCl
0,05(mol)---->0,025(mol)
=>vH2SO4=\(\frac{0,025}{1}\)=0,025(lít)
c)pH=-log(0,25)=0,602
(câu c mình không chắc chắn lắm nha bạn!!!)
Cho mình hỏi s [K+]=[Cl-]=0,25M đc z. Mình chưa hiểu lắm
Cả 2 đều 0,1M?
\(n_{Na^+}=0,1.0,1+2.0,1.0,1=0,03\left(mol\right)\)
\(\Rightarrow\left[Na^+\right]=\dfrac{0,03}{0,1}=0,3M\)
\(n_{Cl^-}=0,1.0,1=0,01\left(mol\right)\Rightarrow\left[Cl^-\right]=0,1M\)
\(n_{SO_4^{2-}}=0,1.0,1=0,01\left(mol\right)\Rightarrow\left[SO_4^{2-}\right]=0,1M\)