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\(=\frac{1.2.4\left(1+2.2.2+4.4.4+8.8.8+16.16.16\right)}{1.3.4\left(1+2.2.2+4.4.4+8.8.8+16.16.16\right)}=\frac{2}{3}\)
\(\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}\)
=\(\frac{4.2+2.8.2.2+4.16.4.2+8.32.8.2}{4.3+2.8.2.3+4.16.4.3+8.32.8.3}\)
=\(\frac{2.\left(4+2.8.2+4.16.4+8.32.8\right)}{3.\left(4+2.8.2+4.16.4+8.32.8\right)}\)
=\(\frac{2}{3}\)
Ủng hộ mik nhé !!!
Đặt biểu thức trên là A. Ta có:
A=\(\frac{2^3+2^6+2^9+2^{12}}{2^2.3+2^5.3+2^8.3+2^{11}.3}\)
=\(\frac{2^3.\left(1+2^3+2^6+2^9\right)}{2^2.3.\left(1+2^3+2^6+2^9\right)}\)
= \(\frac{2^3}{2^2.3}\)
=\(\frac{2}{3}\)
\(\dfrac{\text{2.4 + 2.4.8 + 4.8.16 + 8.16.32 + 16.32.64 }}{3.4+2.6.8+4.12.16+8.24.32+16.48.64}\)
= \(\dfrac{2+4+8+16+32}{3+6+12+24+48}\)= \(\dfrac{2+2+2+2+2}{3+3+3+3+3}\)
= \(\dfrac{10}{15}\) = \(\dfrac{2}{3}\)
\(\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.16.32}\)
\(=\frac{2.\left(4+2.2.8+4.4.16+8.8.32\right)}{3.\left(4+2.2.8+4.4.16+8.8.32\right)}\)
\(=\frac{2}{3}\)
\(\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}=\frac{2.4+2.4.2.2.2.2+4.2.4.4.4+4.2.2.4.2.4.8}{3.4+2.3.2.4.2+4.3.4.4.4+4.2.4.3.2.4.8}\)
\(=\frac{2.4\left(1+2.2.2+4.4.4+2.4.2.4.8\right)}{3.4\left(1+2.2.2+4.4.4+2.4.2.4.8\right)}\)
\(=\frac{2.4}{3.4}\)
\(=\frac{2}{3}\)