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b)a) A = (-1436) - (-1586) + |-532| - (568+468) + 1434
A=-1436+1586+532-1036+1434
A=150+532-1036+1434=1080
b)B=\(\frac{18^6.2^{12}.4^3.9^3}{16^3.6^9.27^3}=\frac{2^6.3^{12}.2^{12}.2^6.3^6}{2^9.2^9.3^9.3^9}=\frac{2^{24}.3^{18}}{2^{18}.3^{18}}=2^6\)
\(A=\frac{18^4.2^{12}.4^3.9^3}{16^3.6^9.27^3}\)
\(A=\frac{\left(3.3.2\right)^4.2^{12}.\left(2^2\right)^3.\left(3^2\right)^3}{\left(4^2\right)^3.\left(3.2\right)^9.\left(3^3\right)^3}\)
\(A=\frac{3^{14}.2^{22}}{2^{21}.3^{18}}\)
\(A=\frac{2}{3^4}\)
\(A=\frac{2}{81}\)
CHÚC BN HỌC TỐT!!!!
a: \(A=\dfrac{16^5\cdot15^5}{2^{10}\cdot3^5\cdot5^4}=\dfrac{2^{20}\cdot3^5\cdot5^5}{2^{10}\cdot3^5\cdot5^4}=2^{10}\cdot5=5120\)
b: \(B=\dfrac{2^{15}\cdot3+2^{19}\cdot10}{2^{12}\cdot26}=\dfrac{2^{15}\left(3+2^4\cdot10\right)}{2^{13}\cdot13}=2^2\cdot\dfrac{163}{13}=\dfrac{652}{13}\)
1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)
\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)
\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)
\(=\dfrac{40+\left(-135\right)+30}{180}\)
\(=\dfrac{-65}{180}\)
\(=\dfrac{-13}{36}\)
2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)
\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)
\(=\dfrac{-21}{36}-\dfrac{22}{36}\)
\(=\dfrac{-21-22}{36}\)
\(=\dfrac{-43}{36}\)
3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)
\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)
\(=\dfrac{14}{16}-\dfrac{-5}{16}\)
\(=\dfrac{14-\left(-5\right)}{16}\)
\(=\dfrac{19}{16}\)
4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)
\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)
\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)
\(=\dfrac{30-\left(-72\right)-25}{80}\)
\(=\dfrac{77}{80}\)
a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)
Lần sau bạn lưu ý ghi đầy đủ yêu cầu đề và viết đề bằng công thức toán nhé.
Lời giải:
\(\frac{18^2.2^{12}.4^3.9^3}{16^3.6^9.27^3}=\frac{(3^2.2)^2.2^{12}.(2^2)^3.(3^2)^3}{(2^4)^3.(2.3)^9.(3^3)^3}=\frac{3^4.2^2.2^{12}.2^6.3^6}{2^{12}.2^9.3^9.3^9}\)
\(=\frac{2^{2+12+6}.3^{4+6}}{2^{12+9}.3^{9+9}}=\frac{2^{20}.3^{10}}{2^{21}.3^{18}}=\frac{1}{2.3^8}=\frac{1}{13122}\)