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\(\dfrac{11}{26}+\dfrac{32}{39}-\left(-\dfrac{14}{52}\right)\)
=\(\dfrac{97}{78}+\dfrac{14}{52}\)
=\(\dfrac{59}{39}\)
a) 5.22 + (x + 3) = 52
5.4 + (x + 3) = 25
20 + (x + 3) = 25
x + 3 = 25 – 20
x + 3 = 5
x = 5 – 3 = 2
b) 23 + (x – 32) = 53 - 43
8 + (x – 9) = 125 – 64
8 + (x – 9) = 61
x – 9 = 61 – 8
x – 9 = 53
x = 53 + 9 = 62
a) \(5.2^2+\left(x+3\right)=5^2\)
\(x+3=5^2-5.2^2\)
\(x+3=25-20\)
\(x+3=5\)
\(x=2\)
b) \(2^3+\left(x-3^2\right)=5^3-4^3\)
\(8+\left(x-9\right)=125-64\)
\(x-9=53\)
\(x=62\)
a, \(6.x.5.\left(x-2\right)=23\)
\(\Leftrightarrow30x.\left(x-2\right)=23\)
\(\Leftrightarrow\orbr{\begin{cases}30x=1\\x-20=23\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{30}\\x=43\end{cases}}\left(1\right)}\)
\(\Leftrightarrow\orbr{\begin{cases}30x=23\\x-20=1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{23}{30}\\x=21\end{cases}\left(2\right)}}\)
\(\Leftrightarrow\orbr{\begin{cases}30x=-1\\x-20=-23\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{30}\\x=-3\end{cases}}\left(3\right)}\)
\(\Leftrightarrow\orbr{\begin{cases}30x=-23\\x-20=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-\frac{23}{30}\\x=19\end{cases}}}\)
b, \(42-\left(2x+32\right)+12:2=6\)
\(\Leftrightarrow42-\left(2x+32\right)+6=6\)
\(\Leftrightarrow42-\left(2x+32\right)=0\)
\(\Leftrightarrow2x-32=42\)
\(\Leftrightarrow2x=74\)
\(\Leftrightarrow x=37\)
\(x^5=32\)
\(\Rightarrow x=2\), vì \(2^5\)= 2.2.2.2.2 = 32
Vậy x = 2
\(3^x.3=243\)
\(3^x=243:3\)
\(3^x=81\)
\(\Rightarrow x=4\)
Vậy x = 4
\(2^x.7=56\)
\(2^x=56:7\)
\(2^x=8\)
\(\Rightarrow x=3\)
Vậy x = 3
a) \(x^5=32\)
\(\Rightarrow x^5=2^5\)
\(\Rightarrow x=2\)
b) \(3^x.3=243\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\Rightarrow x=4\)
c) \(2^x.7=56\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\Rightarrow x=3\)
7 . (-2)^3 - 60:15
= 7 . (-8) - 4
= (-56)- 4
= - 60
125 - (-75) + 32 - (48 + 32)
= 125-75 + 32 - 48 -32
= 50 + (-48)
=2
18 * 23 +3 +45 * 6 +9 * 32 *2 =1263
425 *7*4 - 170 *60=1700
132 *9 +132 =1320
( 56* 27 +56 +35 ):62=\(\frac{1603}{62}\)
39 * ( 250 +87) +61 * ( 240 +97)=33700
Hk tốt!!! k cho mình nha!!@@
a: =-12/20+5/20-6/20
=-13/20
b: =10/50-45/50-14/50
=-49/50
c: =31/23-7/32-8/23=1-7/32=25/32
`#3107.101107`
a,
`2x + 3x = 5^7 \div 5^5`
$\Rightarrow (2 + 3)x = 5^{7 - 5}$
$\Rightarrow 5x = 5^2$
$\Rightarrow 5x = 25$
$\Rightarrow x = 25 \div 5$
$\Rightarrow x = 5$
Vậy, `x = 5`
b,
`5(7x - 45) = 2^3 . 5^2 - 3^2 . 20`
`\Rightarrow 5(7x - 45) = 8.25 - 9.20`
`\Rightarrow 5(7x - 45) = 40.5 - 36.5`
`\Rightarrow 5(7x - 45) = 5.(40 - 36)`
`\Rightarrow 5(7x - 45) = 5.4`
`\Rightarrow 7x - 45 = 4`
`\Rightarrow 7x = 49`
`\Rightarrow x = 49 \div 7`
`\Rightarrow x = 7`
Vậy, `x = 7.`
A) (2+3).x=5 mũ 2
5.x=5 mũ 2
5.x=25
x=25:5
x=5
vậy x=5
câu B ko bt làm bn ạ
\(3^2\left(x+4\right)-5^2=5\cdot2^2\\ 9\left(x+4\right)-25=20\\ 9\left(x+4\right)=20+25\\ 9\left(x+4\right)=45\\ x+4=45:9\\ x+4=5\\ x=5-4\\ x=1\)
52-2(3x-6)=10 3636:(12x-91)=36 2x+3=32
2(3x-6)=52-10 12x-91=3636:36 2x=32-3
2(3x-6)=42 12x-91=101 2x=29
3x-6=42:2 12x=101+91 x=29:2 (loại vì x thuộc N)
3x-6=21 12x=192
3x=21+6 x=192:12=16
3x=27
x=27:3=9
2x.8=512 (24-x)3=64
2x=512:8 (24-x)3=43
2x=64 => 24-x=4
x=64:2=32 x=24-4=20
a,52-2(3x-6)=10
2(3x-6)=52-19=42
3x-6=42:2=21
3x=21+6=27
x=27:3
x=9
b,3636:(12x-91)=36
12x-91=3636:36=101
12x=101+91=192
x=192:12
x=16
c,2x+3=32
2x=32-3=29
x=29:2
x=29/2.Vì x thuộc tập số tự nhiên=> không tồn tại x thỏa mãn đề bài
d,2x.8=512
2x=512:8=64
x=64:2
x=32
e,(24-x)^3=64
(24-x)^3=4^3
=>24-x=4
x=24-4
x=20
a, \(5^2.2^3+3^2.7-8^2.2\)
= 25 . 8 + 27 . 7 - 64 . 2
= 200 + 189 - 128
= 261
b,\(\left(5.2^2-20\right):5+3^2.6\)
= (5 . 4 - 20 ) : 5 + 9 . 6
=( 20 - 20 ) : 5 + 54
= 0: 5 + 54
= 0 + 54
= 54