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\(S=1+2+3-4-5+6+7+8-9-10+...+2011+2012+2013-2014-2015\)
\(=\left(1+2+3-4-5\right)+\left(6+7+8-9-10\right)+...+\left(2011+2012+2013-2014-2015\right)\)
\(=\left(-3\right)+2+...+2007\)
Từ 2 đến 2007 sẽ có: \(\dfrac{2007-2}{5}+1=402\left(số\right)\)
Tổng của dãy số 2;7;12;...;2007 sẽ là:
\(\dfrac{\left(2007+2\right)\cdot402}{2}=403809\)
=>S=403809-3=403806
S = 1/5.6 + 1/10.9+....+ 1/3350.2013
=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)
=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)
= 1/15 .( 1 - 1/671 )
= 1/15 .670/671
=134/2013
S = 1/5.6 + 1/10.9+....+ 1/3350.2013
=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)
=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)
= 1/15 .( 1 - 1/671 )
= 1/15 .670/671
=134/2013
S = 1/5.6 + 1/10.9+....+ 1/3350.2013
=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)
=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)
= 1/15 .( 1 - 1/671 )
= 1/15 .670/671
=134/2013
S = 1/5.6 + 1/10.9+....+ 1/3350.2013
=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)
=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)
= 1/15 .( 1 - 1/671 )
= 1/15 .670/671
=134/2013
S = 1/5.6 + 1/10.9+....+ 1/3350.2013
=1/5 . 1/3 .( 1/2+ 1/2.3 + 1/3.4 +... + 1/670.671)
=1/15. ( 1-1/2 + 1/2 - 1/3+...+ 1/670-1/671)
= 1/15 .( 1 - 1/671 )
= 1/15 .670/671
=134/2013
S = \(\frac{1}{5.6}+\frac{1}{10.9}+\frac{1}{15.12}+...+\frac{1}{3350.2013}=\frac{1}{5.3}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{670.671}\right)\)
\(=\frac{1}{15}\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{670}-\frac{1}{671}\right)=\frac{1}{15}\left(1-\frac{1}{671}\right)=\frac{1}{15}.\frac{670}{671}\)
\(=\frac{134}{2013}\)
A=-1+(-2+3+4-5)+(-6+7+8-9)+(-10+11+12-13)+.......+(-2010+2011+2012-2013)+(-2014+2015+2016)
A=-1+0+0+0+...+0+2017
A=2018
A = -1 - 2 + 3 + 4 - 5 - 6 + 7 + 8 - 9 - 10 + 11 + 12 - ... - 2013 - 2014 + 2015 + 2016
=> A = (-1 - 2 + 3 + 4) + (-5 - 6 + 7 + 8) + (-9 - 10 + 11 + 12) + ... + (-2013 - 2014 + 2015 + 2016)
=> A = 4 + 4 + 4 + ... + 4
có 2016 : 4 = 504 (số 4)
=> A = 4 . 504
=> A = 2016