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a) 3/2:9/4+21/8
= 3/2 x 4/9 + 21/8
=12/18 + 21/8
= 2/3 + 21/8 = 16/24 + 63/24 = 79/24
b) 3/10+5/2x1/3
=3/10 + 5/6
= 9/30 + 25/30 = 34/30 = 17/15
c) 8/15:3/11+2/15:2/11
= 8/15x11/3 + 2/15x11/2
= 88/45 + 22/30
= 88/45 + 11/15 = 88/45 + 33/45 = 121/45
d) 19/5-11/4:9/8
= 19/5 - 11/4x8/9
= 19/5 - 88/36
= 19/5 - 22/9 = 171/45 - 110/45 = 61/45
e) 33/7:11/6+37/15x21/74
= 33/7x6/11 + 7/10
= 198/77 + 7/10 = 1980/770 + 1386/770 = 153/35
a) 3/2:9/4+21/8
= 3/2 x 4/9 + 21/8
=12/18 + 21/8
= 2/3 + 21/8 = 16/24 + 63/24 = 79/24
b) 3/10+5/2x1/3
=3/10 + 5/6
= 9/30 + 25/30 = 34/30 = 17/15
c) 8/15:3/11+2/15:2/11
= 8/15x11/3 + 2/15x11/2
= 88/45 + 22/30
= 88/45 + 11/15 = 88/45 + 33/45 = 121/45
d) 19/5-11/4:9/8
= 19/5 - 11/4x8/9
= 19/5 - 88/36
= 19/5 - 22/9 = 171/45 - 110/45 = 61/45
e) 33/7:11/6+37/15x21/74
= 33/7x6/11 + 7/10
= 198/77 + 7/10 = 1980/770 + 1386/770 = 153/35
99-97+95-93+91-89+...+7-5+3-1
Số các số hạng là:
(99-1):2+1=50 số
=(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1)
Số cặp sẽ là:
50:2=25 cặp
=2+2+2+...+2+2
=2x25
=50
32x47+32-53+168+79+132
=1504+32-53+(168+79+132)
=1536-53+379
=1483+379
=1862
25/2+25/3-25/7/1/3+1/3-1/7
\(=\frac{25}{2}+\frac{25}{3}-\frac{25}{7}:\frac{1}{3}+\frac{1}{3}-\frac{1}{7}\)
\(=\frac{25}{2}+\frac{25}{3}-\frac{25}{7}\times\frac{3}{1}+\frac{1}{3}-\frac{1}{7}\)
\(=\frac{25}{2}+\frac{25}{3}-\frac{156}{7}+\frac{1}{3}-\frac{1}{7}\)
\(=\frac{525}{42}+\frac{350}{42}-\frac{936}{42}+\frac{14}{42}-\frac{6}{42}\)
\(=\frac{875}{42}-\frac{936}{42}+\frac{14}{42}-\frac{6}{42}\)
\(=\frac{-61}{42}+\frac{14}{42}-\frac{6}{42}\)
\(=\frac{-47}{42}-\frac{6}{42}\)
\(=\frac{-53}{42}\)
( Chú Ý: lớp 5 chưa học số âm )
đầu bài: 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
= (1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+20
= 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 + 20 +20
= 20.10
= 200
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20=\(\frac{\left(1+20\right)20}{2}\)=210
a.1+3+5+7+9+11+13+15+17+19
muốn tính tổng của dãy ta lấy tổng số đầu và cuối nhân số các số hạng rồi chia 2.
tổng của dãy:(19+1)x10:2=100
a) \(\frac{3}{3.5}+\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{97.99}\)
\(=\frac{3}{2}.\left(\frac{1}{3}-\frac{1}{5}\right)+\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{7}\right)+\frac{3}{2}.\left(\frac{1}{7}-\frac{1}{9}\right)+...+\frac{3}{2}.\left(\frac{1}{97}-\frac{1}{99}\right)\)
\(=\frac{3}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(=\frac{3}{2}.\left(\frac{1}{3}-\frac{1}{99}\right)\)
\(=\frac{3}{2}.\frac{32}{99}\)
\(=\frac{16}{33}\)
b)
\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{100.103}\)
\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{100}-\frac{1}{103}\)
\(=1-\frac{1}{103}\)
\(=\frac{102}{103}\)
b) 1,2x53+53x17,2-53x8,4
= 8,4x(1,2+17,2+8,4)
=8,4x 10
= 84
d) 1/4x152/11+68/11x1/4
=1/4x( 152/11+68/11)
=1/4x 20
= 5
e) 37x38-19x74+1000
=37x2x19-19x74+1000
=74x19-19x74+1000
=0+1000
=1000