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26 tháng 2 2018

\(C=\frac{-1}{2}+\frac{3}{21}+\frac{-2}{6}+\frac{-5}{30}\)

\(C=\frac{-1}{2}+\frac{1}{7}+\frac{-1}{2}+\frac{-1}{6}\)

\(C=\left(\frac{-1}{2}+\frac{-1}{2}\right)+\left(\frac{1}{7}+\frac{-1}{6}\right)\)

\(C=\frac{-2}{2}+\frac{-1}{42}\)

\(C=-1+\frac{-1}{42}\)

26 tháng 2 2018

thế kết quả = bao nhiêu

19 tháng 7 2023

Bài 6:

\(21,251+6,058+0,749+1,042\)

\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)

\(=22+7,1\)

\(=29,1\)

___________________

\(1,53+5,309+12,47+5,691\)

\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)

\(=14+11\)

\(=25\)

5:

a: =>x/17=5/17

=>x=5

b; =>6+x=7/11*33=21

=>x=15

c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)

=>3x+36=86-2x

=>5x=50

=>x=10

d: \(\dfrac{x}{5}< \dfrac{3}{7}\)

=>x<3/7*5

=>x<15/7

f: 15/26+x/16=46/52

=>x/16=23/26-15/26=8/26=4/13

=>x=4/13*16=64/13

AH
Akai Haruma
Giáo viên
30 tháng 9

Lời giải:

$\frac{1}{2}+\frac{3}{21}+\frac{-2}{6}+\frac{-5}{30}$

$=\frac{1}{2}+\frac{1}{7}-\frac{1}{3}-\frac{1}{6}$
$=(\frac{1}{2}-\frac{1}{3}-\frac{1}{6})+\frac{1}{7}$
$=0+\frac{1}{7}=\frac{1}{7}$

25 tháng 3 2015

        C = -1/2 +3/21 +-2/6 + -5/30

           = -1/2 + 1/7 ( rút gọn 3/21 cho 3 ) + -1/3 (rút gọn cho 2 ) + -1/6 (rút gọn cho 6)

          =( -1/2 +  -1/3 ) + 1/7 + -1/6

        =  -5/6  + 1/7 + -1/6

           = (-5/6 + -1/6 ) + 1/7

            = -1 +1/7

           = -7/7 + 1/7

          = -6/7

Bài 2: 

a: A=(12,87+14,13)+(-14,7-37,3)

=27-52=-25

b: B=-1/3+2/5-2/3-3/5+1/5

=-1

21 tháng 5 2015

-6/7

đúng nghen bạn

8 tháng 3 2018

c=-1/2+3/21+-2/6+-5/30

=-5/14-2/6-5/30

=-29/42-5/30

=-6/7

AH
Akai Haruma
Giáo viên
29 tháng 10

Lời giải:

$C=\frac{-1}{2}+\frac{3}{21}+\frac{-2}{6}+\frac{-5}{30}$

$=\frac{-1}{2}+\frac{1}{7}+\frac{-1}{3}+\frac{-1}{6}$

$=\frac{1}{7}-(\frac{1}{2}+\frac{1}{3}+\frac{1}{6})$

$=\frac{1}{7}-1=\frac{-6}{7}$

Bài 1: 

\(A=\dfrac{-1}{3}+1+\dfrac{1}{3}=1\)

\(B=\dfrac{2}{15}+\dfrac{5}{9}-\dfrac{6}{9}=\dfrac{2}{15}-\dfrac{1}{9}=\dfrac{18-15}{135}=\dfrac{3}{135}=\dfrac{1}{45}\)

\(C=\dfrac{-1}{5}+\dfrac{1}{4}-\dfrac{3}{4}=\dfrac{-1}{5}-\dfrac{1}{2}=\dfrac{-7}{10}\)

Bài 2: 

a: \(=\dfrac{1}{5}+\dfrac{1}{2}+\dfrac{2}{5}-\dfrac{3}{5}+\dfrac{2}{21}-\dfrac{10}{21}+\dfrac{3}{20}\)

\(=\left(\dfrac{1}{5}+\dfrac{2}{5}-\dfrac{3}{5}\right)+\left(\dfrac{2}{21}-\dfrac{10}{21}\right)+\left(\dfrac{1}{2}+\dfrac{3}{20}\right)\)

\(=\dfrac{-8}{21}+\dfrac{13}{20}=\dfrac{113}{420}\)

b: \(B=\dfrac{21}{23}-\dfrac{21}{23}+\dfrac{125}{93}-\dfrac{125}{143}=\dfrac{6250}{13299}\)

30 tháng 1 2022

Bài 3:

\(\dfrac{7}{3}-\dfrac{1}{2}-\left(-\dfrac{3}{70}\right)=\dfrac{7}{3}-\dfrac{1}{2}+\dfrac{3}{70}=\dfrac{490}{210}-\dfrac{105}{210}+\dfrac{9}{210}=\dfrac{394}{210}=\dfrac{197}{105}\)

\(\dfrac{5}{12}-\dfrac{3}{-16}+\dfrac{3}{4}=\dfrac{5}{12}+\dfrac{3}{16}+\dfrac{3}{4}=\dfrac{20}{48}+\dfrac{9}{48}+\dfrac{36}{48}=\dfrac{65}{48}\)

Bài 4:

 \(\dfrac{3}{4}-x=1\)

\(\Rightarrow-x=1-\dfrac{3}{4}\)

\(\Rightarrow x=-\dfrac{1}{4}\)

Vậy: \(x=-\dfrac{1}{4}\)

\(x+4=\dfrac{1}{5}\)

\(\Rightarrow x=\dfrac{1}{5}-4\)

\(\Rightarrow x=-\dfrac{19}{5}\)

Vậy: \(x=-\dfrac{19}{5}\)

\(x-\dfrac{1}{5}=2\)

\(\Rightarrow x=2+\dfrac{1}{5}\)

\(\Rightarrow x=\dfrac{11}{5}\)

Vậy: \(x=\dfrac{11}{5}\)

\(x+\dfrac{5}{3}=\dfrac{1}{81}\)

\(\Rightarrow x=\dfrac{1}{81}-\dfrac{5}{3}\)

\(\Rightarrow x=-\dfrac{134}{81}\)

Vậy: \(x=-\dfrac{134}{81}\)

c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)

\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)

\(=1-2=-1\)

Giải:

a)-1/12+4/3=-1/12+16/12=15/12=5/4

b)(-4/14-3/15)-(1/5-20/35-(-1)).7

=-17/35-22/35.7

=-17/35-22/5

=-171/35

c)3/5+-5/20+30/75+-7/4

=3/5+-1/4+2/5+-7/4

=(3/5+2/5)+(-1/4+-7/4)

=1+-2

=-1

d)5/6.-12/14+7/13

=-5/7+7/13

=-16/91

e)2/-9-5/-36-1/4

=-1/12-1/4

=-1/3

f)2/23+-5/12+7/18+21/23+-7/12

=(2/23+21/23)+(-5/12+-7/12)+7/18

=1+-1+7/18

=7/18