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\(B=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3.2^2.2^{16.2}}{11.2^{13}.2^{22}-2^{36}}=\frac{3.2^{34}}{11.2^{35}-2^{36}}=\frac{3.2^{34}}{2^{34}\left(11.2-2^2\right)}\)
\(=\frac{3}{11.2-2^2}=\frac{3}{11.2-4}=\frac{3}{22-4}=\frac{3}{18}=\frac{1}{6}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{9.\left(2^2\right)^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{9.2^4.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{9.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2^{35}.2}{2^{35}.9}\)
\(=2\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.4^2.2^{32}}{2^{35}\left(11-2\right)}\)
\(=\frac{3^2.4^2.2^{32}}{2^{35}.3^2}\)
\(=\frac{4^2}{2^3}\)
\(=\frac{2^4}{2^3}\)
\(=2\)
Hk tốt
= 3^2 . 2^4 . 2^32 / 11.2^13 .2^22 - 2^36
=3^2 . 2^36 / 11.2^35 - 2^36
=3^2 . 2^36 / 2^35 . ( 11+2)
= 9 . 2^36 / 2^35 . 13
= 9 . 2 / 13 = 18/13
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{2^{35}\left(9+2\right)}{2^{35}\left(11-2\right)}=\frac{11}{9}\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{35}.2}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2^{35}.2}{2^{35}.9}\)
\(=2\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
= \(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
= \(\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{35}.2}\)
= \(\frac{3^2.2^4.2^{32}}{2^{35}.\left(11-2\right)}\)
= \(\frac{3^2.2^{36}}{2^{35}.9}\)
= \(\frac{9.2^{35}.2}{2^{35}.9}\)
= \(2\)
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)