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\(\frac{\left(43-11\right)\left(43+11\right)}{\left(36,5-27,5\right)\left(36,5+27,5\right)}=\frac{32.54}{9.64}\)
\(=3\)
dùng hằng đẳng thức thứ 3 ta có
(43-11)(43+11) và (36,5-27,5)(36,5+27,5)
Nên =1728 : 576=3
\(R=\frac{43^2-11^2}{36,5^2-27,5^2}\)
\(R=\frac{\left(43-11\right)\left(43+11\right)}{\left(36,5+27,5\right)\left(36,5-27,5\right)}\)
\(R=\frac{32.54}{64.9}\)
\(R=3\)
\(R=\frac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
\(=\frac{\left(43-11\right)\left(43+11\right)}{\left(36,5-27,5\right)\left(36,5+27,5\right)}\)
\(=\frac{32.54}{9.64}\)
\(=\frac{6}{2}=3\)
Bạn viết sai đề bài rồi
\(S=\frac{97^3+83^3}{180}-97.83\)
\(=\frac{\left(97+83\right)\left(97^2-97.83+83^2\right)}{180}-97.83\)
\(=97^2-97.83+83-97.83\)
\(=\left(97-83\right)^2=14^2=196\)
Trả lời:
\(R=\frac{43^2-11^2}{36,5^2-27,5^2}\)
\(R=\frac{\left(43-11\right).\left(43+11\right)}{\left(36,5-27,5\right).\left(36,5+27,5\right)}\)
\(R=\frac{32.54}{9.64}\)
\(R=3\)
Đề bài sai bạn nhé
\(S=\frac{97^3+83^3}{180}-97.83\)
\(S=\frac{\left(97+83\right).\left(97^2-97.23+83^2\right)}{180}-97.83\)
\(S=97^2-97.83+83^2-97.83\)
\(S=97^2-2.97.83+83^2\)
\(S=\left(97-83\right)^2\)
\(S=14^2\)
\(S=196\)
\(A=\dfrac{\left(43-11\right)\left(43+11\right)}{\left(36.5-27.5\right)\left(36.5+27.5\right)}\)
\(=\dfrac{32\cdot54}{9\cdot64}=\dfrac{1}{2}\cdot6=3\)
1
a,
=(202+54).(202-54)+256.352
=37888+256.352
=37888+90112
=128000
b,
=621-769.373-21904
=621-286837-21904
=-308120
c,
42^2-10^2/(36,5)^2-(27,5)^2
=(42-10).(42+10)/(36,5-27,5).(27,5+36,5)
=1664/576=2(8)
1. Tính nhanh :
a) \(202^2-54^2+256.352\)
\(=\left(202-54\right).\left(202+54\right)+256.352\)
\(=148.256+256.352\)
\(=256.\left(148+252\right)=256.400=102400\)
a,Ta có A=\(\dfrac{\left(54-23\right)\left(54+23\right)}{\left(36,5-25,5\right)\left(36,5+25,5\right)}=\dfrac{31.77}{11.62}=\dfrac{7}{2}\)
b,Ta có B=\(\dfrac{\left(82-34\right)\left(82+34\right)}{\left(30,5-1,5\right)\left(30,5+1,5\right)}=\dfrac{48.116}{29.32}=\dfrac{6.8.4.29}{29.8.4}=6\)
c,Ta có C=\(\dfrac{\left(86-54\right)\left(86^2+86.54+54^2\right)}{32}+86.54=86^2+86.54+54^2+86.54=\left(86+54\right)^2=19600\)
\(A=\dfrac{43^2-11^2}{\left(36,5\right)^2-\left(27,5\right)^2}\)
\(=\dfrac{\left(43-11\right)\left(43+11\right)}{\left(36,5-27,5\right)\left(36,5+27,5\right)}\)
\(=\dfrac{32.54}{9.64}=\dfrac{6}{2}=3\)