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\(\frac{121212}{141414}\times\frac{1313}{1212}\times\frac{2424}{2424}\)
\(=\frac{6}{7}\times\frac{13}{12}\times1\)
\(=\frac{13}{14}\)
~ Hok tốt ~
\(2018\times\left(\frac{1}{2}+\frac{1212}{2424}\right)=2018\times\left(\frac{1}{2}+\frac{12}{24}\right).\)
\(=2018\times\left(\frac{1}{2}+\frac{1}{2}\right)\)
\(=2018\times1=2018\)
\(8\times\frac{3333}{2424}\times54\)
\(=8\times\frac{11}{8}\times54\)
\(=11\times54\)
\(=594\)
1212/2727= 1212:101/2727:101= 12/17
361361/789789= 361361:1001/789789:1001= 361/789
Ta có: \(\frac{1212}{1313}=\frac{12x101}{13x101}=\frac{12}{13}\)
Vậy \(\frac{12}{13}=\frac{1212}{1313}\)
Ta có: 1212/1313 = 12.101/13.101= 12/13
Vì 12/13 = 12/13 nên 12/13 = 1212/1313
Vây...
\(\frac{3}{2}>1;\frac{1212}{3232}< 1\)\(\Rightarrow\frac{3}{2}>\frac{1212}{3232}\)
Ta có:
\(\frac{3}{2}>\frac{2}{2}=1.\)
Mà \(\frac{1212}{3232}< \frac{3232}{3232}=1.\)
=>\(\frac{3}{2}>1>\frac{1212}{3232}\)
Vậy \(\frac{3}{2}>\frac{1212}{3232.}\)
Ko cần tk mk đâu mk tl cho vui thôi nhá.
-Chúc mọi người vui vẻ-
8x3333/2424x54
=8x 3333:303/2424:303 x54 (Vì 3333/2424 chưa rút gọn)
=8x11/8x54
=11x54=594
bài 1
Ta có : 2016/2017<1
2017/2018<1
Nên 2016/2017=2017/2018
Bài 1 :
a) Ta có : \(\frac{2016}{2017}=1-\frac{1}{2017}\)
\(\frac{2017}{2018}=1-\frac{1}{2018}\)
Vì \(-\frac{1}{2017}< -\frac{1}{2018}\)nên \(\frac{2016}{2017}< \frac{2017}{2018}\)
b) Ta có : \(\frac{2018}{2017}=1+\frac{1}{2017}\)
\(\frac{2017}{2016}=1+\frac{1}{2016}\)
Vì \(\frac{1}{2017}< \frac{1}{2016}\) nên \(\frac{2018}{2017}< \frac{2017}{2016}\)
Câu 2 :
\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{101.103}\)
\(=\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{101.103}\right)\)
\(=\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{101}-\frac{1}{103}\right)\)
\(=\frac{1}{2}.\left(1-\frac{1}{103}\right)\)
\(=\frac{1}{2}.\frac{102}{103}=\frac{51}{103}\)
Trả lời:
\(2018\times\left(\frac{1212}{1212}\div\frac{2424}{2424}\right)\)
\(=2018\times\left(1\div1\right)\)
\(=2018\times1\)
\(=2018\)
Tính nhanh
\(2018\times\left\{\frac{1212}{1212}\div\frac{2424}{2424}\right\}\)
\(=2018\times1\)
\(=2018\)