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Gọi biểu thức này là S , ta có
S =1.2 + 2.3 + 3.4 + 4.5 + ...+ 100.101
3S= 1. 2 .3 + 2. 3 .3 + 3 . 4 .3 + 4 .5 .3 + ...........+ 100 .101 .3
3S= 1.2 (3 - 0) + 2 . 3 .(4 - 1) + 3 . 4. (5 - 2 ) +.......+ 100 . 101 . (102 - 99)
3S = 1 . 2 . 3 - 0 . 1 .2 + 2 . 3 . 4 - 1 . 2 .3 + ................+ 100 . 101 .102 - 99 100 . 101
S = \(\frac{100.101.102}{3}=\frac{100.101.34}{1}\)
S = 343400
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Nhớ **** cho mjk với nhak!!!!!
Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Nhớ **** cko mjk nhak!!
Đặt A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100 + 100.101
3A = 1.2.3 + 2.3.3 + 3.4.3 + 4.5.3 + ... + 99.100.3 + 100.101.3
3A = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98) + 100.101.(102 - 99)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100 + 100.101.102 - 99.100.101
3A = 100.101.102
3A = 1030200
A = 343400
Ta có:
A-B =1.2+2.3+3.4+...+100.101-
(1^2+2^2+3^2+4^2+...+100^2)
= 1.2+2.3+3.4+...+100.101-
Đặt B = 1.2+2.3 +.......+99.100+100.101
3B= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3 + 100.101.3
3B= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98) . 100.101.(102 - 99)
3B = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101 + 100.101.102) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100.99.100.101)
3B = 100.101.102 - 0.1.2
3B = 1030200 - 0
3B= 1030200
B = 1030200 : 3
B = 343400
ĐẶT S = 1.2 + 2.3 +3.4 +........ + 100.101
3S = 1 . 2 .3 + 2 . 3 . 3+ 3.4.3 + ....... + 99 . 100 . 3
3S= 1 . 2 . 3 + 2. 3 . ( 4-1 ) + ......... + 99 . 100 . (101 -98 )
3S= 1 . 2 . 3 + 2 . 3 . 4 - 1 . 2 . 3+ 3 . 4 . 5 - 2 . 3 . 4 + ...... + 99 . 100 . 101 - 98 . 99 . 100
3S = 99 . 100 . 101
3S = 3 .33 . 100 . 101
S= 33 . 100 . 101 = 333300
Đặt A = 1.2+2.3+3.4+...+100.101
3A = 1.2.3+2.3.3+3.4.3+...+100.101.3
3A= 1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+100.101.(102-99)
3A= 1.2.3-0.1.2+2.3.4-1.2.3+...+100.101.102-99.100.101
3A= (1.2.3-1.2.3)+(2.3.4-2.3.4)+...+(99.100.101-99.100.101)+(100.101.102-0.1.2)
3A= 0+0+...+0+(100.101.102-0.1.2)
3A= 100.101.102-0.1.2
3A= 100.101.102
A= (100.101.102):3
A= 1030200:3
A= 343400
B=1.2+2.3+3.4+...+100.101
=>3B=1.2.3+2.3.3+3.4.4+....+100.101.3
=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+....+100.101.102-99.100.101
=-0.1.2-100.101.102
=1030200
=>B=1030200:3=343400
B = 1.2+2.3 +.......+99.100+100.101
3B= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3 + 100.101.3
3B= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98) . 100.101.(102 - 99)
3B = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101 + 100.101.102) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100.99.100.101)
3B = 100.101.102 - 0.1.2
3B = 1030200 - 0
3B= 1030200
B = 1030200 : 3
B = 343400
A = 1.2 + 2.3 + 3.4 + 4.5 + ... + 99.100 + 100.101
3.A = 1.2.3 + 2.3.3 +3.4.3 + ... + 100.101.3
3A= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 100.101.(102 - 99)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 2.3.4 -3.4.5 + ... +99.100.101 -100.101.102
3A = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
Vậy A = 33. 100 .101 (Tự tính)
A = 1.2 + 2.3 + 3.4 + ... + 99.100 + 100.101
⇒ 3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 99.100.3 + 100.101.3
= 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 99.100.(101 - 98) + 100.101.(102 - 99)
= 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + 3.4.5 + ... - 98.99.100 + 99.100.101 - 99.100.101 + 100.101.102
= 100.101.102
= 1030200
⇒ A = 1030200 : 3
= 343400