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\(\left(-\frac{1}{3}\right)^4=\frac{1}{81}\)
\(\left(-2\frac{1}{4}\right)^3=\left(-\frac{9}{4}\right)^3=\frac{-9^3}{4^3}=\frac{-729}{64}\)
\(\left(-0,2\right)^2=0,04\)
\(\left(-5,3\right)^0=1\)
\(\left(\frac{-1}{3}\right)^4=\frac{\left(-1\right)^4}{3^4}=\frac{1}{81}\)
\(\left(-2\frac{1}{4}\right)^3=\left(\frac{-9}{4}\right)^3=\frac{\left(-9\right)^3}{4^3}=\frac{-729}{64}\)
\(\left(-0,2\right)^2=\left(\frac{1}{5}\right)^2=\frac{1^2}{5^2}=\frac{1}{25}\)
\(\left(-5,3\right)^0=1\)
\(\left(\dfrac{-1}{3}\right)^4=\dfrac{\left(-1\right)^4}{3^4}=\dfrac{1}{81}\)
\(\left(-2\dfrac{1}{4}\right)^3=\left(-2\right)^3\cdot\left(\dfrac{1}{4}\right)^3=-8\cdot\dfrac{1}{64}=-0,125\)
\(\left(-0,2\right)^2=0,04\)
\(\left(-5,3\right)^0=1\)
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
= 1/81 ; -729/64 ; 0,04 ; 1