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\(A=\frac{3}{2}\times5+\frac{3}{5}\times8+\frac{3}{8}\times11+.....+\frac{3}{20}\times23+\frac{3}{23}\times26\)
\(A=\frac{3}{2}\times\frac{5}{1}+\frac{3}{5}\times\frac{8}{1}+\frac{3}{8}\times\frac{11}{1}+.....+\frac{3}{20}\times\frac{23}{1}+\frac{3}{23}\times\frac{26}{1}\)
\(A=\left(\frac{3}{2}\times\frac{5}{1}+\frac{3}{23}\times\frac{26}{1}\right)+.....+\left(\frac{3}{11}\times\frac{14}{1}+\frac{3}{14}\times\frac{17}{1}\right)\)CÓ 8 CẶP
\(A=\left(\frac{15}{2}+\frac{68}{23}\right)+.....+\left(\frac{42}{11}+\frac{51}{14}\right)\)
\(A=\left(\frac{15}{2}+\frac{68}{23}\right)+.....+\left(\frac{42}{11}+\frac{51}{14}\right)\)
CÒN LẠI TỰ GIẢI NHA
9/14 .<.. 11/14 4/25 .<.. 4/23 5/6 ..<. 7/8 1 ..>. 14/15
8/9 ..=. 24/27 20/19 ..>. 20/27 8/7 .>.. 9/8 1 .<..15/14
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
\(G=\dfrac{7}{8}+\dfrac{11}{24}+\dfrac{5}{8}+\dfrac{23}{24}+\dfrac{11}{8}+\dfrac{13}{24}\\ \Rightarrow G=\left(\dfrac{7}{8}+\dfrac{5}{8}+\dfrac{11}{8}\right)+\left(\dfrac{11}{24}+\dfrac{23}{24}+\dfrac{13}{24}\right)\\ \Rightarrow G=\dfrac{23}{8}+\dfrac{47}{24}\\ \Rightarrow G=\dfrac{69}{24}+\dfrac{47}{24}\\ \Rightarrow G=\dfrac{116}{24}\\ \Rightarrow G=\dfrac{29}{6}\)
13/19 x 23/11 - 13/19 x 8/11 - 13/19 x 4/11
= 13/19 x (23/11 - 8/11 - 4/11)
= 13/19 x 1
= 13/19
\(\dfrac{13}{19}\times\dfrac{23}{11}-\dfrac{13}{19}\times\dfrac{8}{11}-\dfrac{13}{19}\times\dfrac{4}{11}\\ =\dfrac{13}{19}\times\left(\dfrac{23}{11}-\dfrac{8}{11}-\dfrac{4}{11}\right)\\ =\dfrac{13}{19}\times1=\dfrac{13}{19}\)
⇒ \(x=\dfrac{23}{5}:\dfrac{8}{11}\)
⇒ \(x=\dfrac{253}{40}\)
\(\frac{8}{11}.\frac{14}{23}+\frac{8}{11}.\frac{9}{23}-\frac{8}{11}\)
\(=\frac{8}{11}.\left(\frac{14}{23}+\frac{9}{23}\right)-\frac{8}{11}\)
\(=\frac{8}{11}.1-\frac{8}{11}\)
\(=0\)
=8/11x(14/23+9/23)-8/11
=8/11x23/23-8/11
=8/11x1-8/11
=0