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\(1.2.3...9-1.2.3...8-1.2.3...8^2\)
\(=\left(1.2.3...8\right).9-1.2.3...8-1.2.3..8.8\)
\(=\left(1.2.3....8\right)8-1.2.3.4...8\)
\(=1.2.3...8.8-1.2.3...8.8\)
\(=0\)
Bài làm
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3...8.( 9 - 1 - 8 )
= 1.2.3...8 .0
= 0
_Chúc_Bạn_Hok_Tốt_^^
\(1.2.3....9-1.2.3...8-1.2.3...7.8^2=1.2.3....8\left(9-1-8\right)=1.2.3....8.0=0\)
a: \(\dfrac{10^2+11^2+12^2}{13^2+14^2}=\dfrac{100+121+144}{169+196}=\dfrac{365}{365}=1\)
c: \(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot\left(11-2\right)}=2\)
\(b)\) \(1.2.3...9-1.2.3...8-1.2.3...8^2\)
\(=\)\(1.2.3...8\left(9-1-8\right)\)
\(=\)\(1.2.3...8\left(9-9\right)\)
\(=\)\(1.2.3...8.0\)
\(=\)\(0\)
1.2.3.......9-1.2.3...8-1.2.3....82
=1.2.3.......9-1.2.3.........8-1.2.3....8.8
= 1.2.3....8(9-1-8)
=1.2.3......8.0
=0
=1.2.3.4.5.6.7.8 .(9-1-8)
1.2.3.4.5.6.7.8.0=0
Ủng hộ mk nha