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\(\frac{6:\frac{3}{5}-1\frac{1}{6}\cdot\frac{6}{7}}{4\frac{1}{5}\cdot\frac{10}{11}+5\frac{2}{11}}=1\)
\(\frac{6:\frac{3}{5}-1\frac{1}{6}\times\frac{6}{7}}{4\frac{1}{5}\times\frac{10}{11}+5\frac{2}{11}}\)
\(=\frac{\frac{6}{1}:\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}}{\frac{21}{5}\times\frac{10}{11}\times\frac{57}{11}}\)
\(=\frac{\frac{6}{1}\times\frac{5}{3}-1}{\frac{210}{55}+\frac{57}{11}}\)
\(=\frac{\frac{30}{3}-1}{\frac{42}{11}+\frac{57}{11}}\)
\(=\frac{10-1}{\frac{99}{11}}\)
\(=\frac{9}{9}\)
\(=1\)
\(6:\frac{3}{5}-1\frac{1}{6}\)X \(\frac{6}{7}\) \(4\frac{1}{5}\)X \(\frac{10}{11}+5\frac{2}{11}\)
\(=\frac{33}{5}-\frac{7}{6}\)X \(\frac{6}{7}\) \(=\) \(\frac{21}{5}\)X \(\frac{10}{11}+\frac{57}{11}\)
\(=\frac{33}{5}-1\) \(=\frac{42}{11}+\frac{57}{11}\)
\(=\frac{28}{5}\) \(=\frac{99}{11}=9\)
=( 6 x\(\frac{5}{3}\) - \(\frac{7}{6}\) x\(\frac{6}{7}\) ) : (\(\frac{21}{5}\) x\(\frac{10}{11}\) +\(\frac{57}{11}\))
= (10 - 1) :(\(\frac{42}{11}\)+\(\frac{57}{11}\))
=\(\frac{9}{9}\)= 1
Bài 2:
\(B=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).......\left(1-\frac{1}{2004}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{2003}{2004}\)
\(=\frac{1}{2004}\)
\(A=\frac{10-1\frac{1}{6}.\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{11}}=\frac{10-\frac{7}{6}.\frac{6}{7}}{\frac{21.2}{11}+\frac{57}{11}}=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{9}=1\)
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Bài làm
\(\frac{10-1\frac{1}{6}\times\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{12}}\)
\(=\frac{10-\frac{7}{6}\times\frac{6}{7}}{21\times\frac{2}{11}+\frac{62}{12}}\)
\(=\frac{10-1}{\frac{42}{11}+\frac{62}{12}}\)
\(=9:(\frac{42}{11}+\frac{62}{12})\)
\(=9:\left(\frac{504}{132}+\frac{682}{132}\right)\)
\(=9:\frac{1186}{132}\)
\(=9:\frac{593}{66}\)
\(=9\times\frac{66}{593}\)
\(=\frac{594}{593}\)
# Hông bt có đúng k nx. #
a) \(A=10-1\frac{1}{6}.\frac{6}{7}\)
\(=10-\frac{7}{6}.\frac{6}{7}\)
\(=10-1=9\)
b) \(B=21:\frac{11}{2}+5\frac{2}{11}\)
\(=\frac{42}{11}+\frac{57}{11}=9\)
c) \(A=9;B=9\)
\(A.B=9.9=81\)
d) \(A=9;B=9\)
\(A:B=9:9=1\)
a) A = \(10-1\frac{1}{6}\times\frac{6}{7}\)= \(10-\frac{7}{6}\times\frac{6}{7}\)= 10 - 1 = 9
b) B = \(21:\frac{11}{2}+5\frac{2}{11}\)= \(\frac{42}{11}+\frac{57}{11}\)= 9
c) A x B = 9 x 9 = 81
c) A : B = 9 : 9 = 1
\(A=\frac{10-1\frac{1}{6}\times\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{11}}\)
\(A=\frac{10-\frac{7}{6}\times\frac{6}{7}}{21:\frac{11}{2}+\frac{57}{11}}\)
\(A=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}\)
\(A=\frac{9}{9}=1\)