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![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(\left(3x\right)^3-3.\left(3x\right)^2.1+3.3x.2^2-2^3=0\)
\(\left(3x-2\right)^3=0\)
3x-2=0
3x=2
x=2/3
b)
\(x^3-3.x^2.5+3.x.5^2+5^3=0\)
\(\left(x-5\right)^3=0\)
x-5=0
x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=x^3+15x^2+75x+125=\left(x+5\right)^3=-125\)
\(B=4x^2+12xy+9y^2=\left(2x+3y\right)^2=\left(3+6\right)^2=81\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,=\left(x+3\right)^3=\left(-3+3\right)^3=0\\ b,=27x^3+1-\left(1-27x^3\right)=27x^3+1-1+27x^3=54x^3\\ =54\cdot10^3=54\cdot1000=54000\)
c, hình như sai đề á e
![](https://rs.olm.vn/images/avt/0.png?1311)
A = (3x + 1)[(3x)2 - 3x + 12] - (1 - 3x)[12 + 3x + (3x)2]
= (3x)3 + 13 - [13 - (3x)3]
= 27x3 + 1 - 1 + 27x3 = 54x3
Tại x = 10, giá trị của A là:
54 . 103 = 54000
\(A=27x^3+1-\left(1-27x^3\right)\\ A=27x^3+1-1+27x^3=54x^3\\ A=54\cdot10^3=54000\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(M=3\left(3x+1\right)\left(9x^2-3x+1\right)-\left(x^3+1\right)\)
\(=3\left(27x^3+1\right)-x^3-1=80x^3+2=80.\left(\dfrac{1}{2}\right)^3+2=12\)
Sửa đề: \(N=\left(3x+1\right)\left(9x^2-3x+1\right)-\left(x+1\right)\left(x^2-x+1\right)\)
\(N=27x^3+1-x^3-1=26x^3=26.10^3=26000\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(D=x^3-3x^2y+3xy^2-y^3-3x^3+6x^2y-3xy^2+3x^3-3x^2y-x^3\\ D=-y^3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,=\left(3x+\dfrac{y}{2}\right)\left(9x^2+\dfrac{3}{2}xy+\dfrac{y^2}{4}\right)\\ b,=\left(5x+3y\right)\left(25x^2+15xy+9y^2\right)\)
\(a,A=\left(x+5\right)^3=\left(-10+5\right)^3=\left(-5\right)^3=-125\\ b,B=\left(2x+3y\right)^2=\left(2\cdot1+3\cdot2\right)^2=7^2=49\\ c,C=\left(3x-y\right)^3=\left(3\cdot1+2\right)^3=5^3=125\)