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=\(\frac{-11}{23}\)\(\times\)\(\frac{10}{-13}\)\(+\)\(\frac{11}{-13}\)\(\times\)\(\frac{-3}{23}\)\(+\)\(\frac{12}{23}\)
=\(\frac{110}{299}\)\(+\)\(\frac{33}{299}\)\(+\)\(\frac{12}{23}\)
=\(\frac{143}{299}\)\(+\)\(\frac{12}{23}\)
= 1
Xét : 6/13 - 6/17 + 18/23
= 4/13 . 3/2 - 4/17 . 3/2 + 12/23 . 3/2
= 3/2.(4/13-4/17+12/23)
=> D = 1/(3/2) = 2/3
Tk mk nha
\(D=\frac{\frac{4}{13}-\frac{4}{17}+\frac{12}{23}}{\frac{6}{13}-\frac{6}{17}+\frac{18}{23}}=\frac{4}{6}-\frac{4}{6}+\frac{12}{18}=\frac{2}{3}\)
\(A=\frac{17}{23}\cdot\frac{8}{16}\cdot\frac{23}{17}\cdot\left(-80\right)\cdot\frac{3}{4}\)\(=\frac{17\cdot4\cdot2\cdot23\cdot16\cdot\left(-5\right)\cdot3}{23\cdot16\cdot17\cdot4}\)
=> \(A=\frac{2\cdot\left(-5\right)\cdot3}{1}=-30\)
\(B=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right)\left(\frac{1}{3}+\frac{1}{4}-\frac{7}{12}\right)\)
=> \(B=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right)\left(\frac{7}{12}-\frac{7}{12}\right)\)
=> \(B=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right)\cdot0=0\)
a)\(A=\frac{17}{23}.\frac{8}{16}.\frac{23}{17}.\left(-80\right).\frac{3}{4}\)
\(A=\left(\frac{17}{23}.\frac{23}{17}\right).\left(\frac{8}{16}.\frac{3}{4}\right).\left(-80\right)\)
\(A=\frac{3}{8}.\left(-80\right)\)
\(A=-30\)
b)\(C=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right).\left(\frac{1}{3}+\frac{1}{4}-\frac{7}{12}\right)\)
\(C=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right).0\)
\(C=0\)
\(\frac{7}{18}.\left(\frac{-12}{23}-\frac{4}{15}\right)+\frac{7}{18}.\left(\frac{8}{30}+\frac{35}{23}\right)\)
\(=\frac{7}{18}.\left(\frac{-12}{23}-\frac{4}{15}\right)+\frac{7}{18}.\left(\frac{4}{15}+\frac{35}{23}\right)\)
\(=\frac{7}{18}.\left(\frac{-12}{23}-\frac{4}{15}+\frac{4}{15}+\frac{35}{23}\right)\)
\(=\frac{7}{18}.[\left(\frac{-12}{23}+\frac{35}{23}\right)+\left(\frac{-4}{15}+\frac{4}{15}\right)]\)
\(=\frac{7}{18}.1+0\)
\(=\frac{7}{18}\)
_Chúc bạn học tốt_
a: \(=\dfrac{17}{7}+\dfrac{2}{9}-\dfrac{10}{7}-\dfrac{5}{3}\cdot9=1+\dfrac{2}{9}-15=-14+\dfrac{2}{9}=-\dfrac{126}{9}+\dfrac{2}{9}=-\dfrac{124}{9}\)
b: \(=\dfrac{-11}{23}\left(\dfrac{6}{7}+\dfrac{8}{7}\right)-\dfrac{1}{23}=\dfrac{-22}{23}-\dfrac{1}{23}=-1\)
c: \(=\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot\dfrac{4-3-1}{24}=0\)
d: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{15}{2}\)
\(9\frac{8}{23}-\left(5\frac{7}{12}+14\frac{8}{23}\right)\)
\(< =>\frac{215}{23}-\left(\frac{67}{12}+\frac{330}{23}\right)\)
\(< =>\frac{215}{23}-\frac{5501}{276}\)
\(< =>\frac{-127}{12}\)
chuc ban hoc tot nhe >.<
\(\frac{4354}{23}+\frac{2453425}{23}=\frac{4354+2453425}{23}=\frac{2457779}{23}\)
\(\frac{43352}{12}+\frac{23412134}{23}=\frac{997096}{276}+\frac{280945608}{276}=\frac{281942704}{276}\)
\(\frac{4354+2453425}{23}=\frac{2457779}{23}\)