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Ta có:
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{99}\right).\left(1-\frac{1}{100}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}...\frac{98}{99}.\frac{99}{100}\) \(=\frac{1.2.3...98.99}{2.3.4...99.100}=\frac{1}{100}\)
nha
\(T=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}......\frac{575}{576}.\frac{624}{625}\)
\(T=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.....\frac{23.25}{24.24}.\frac{24.26}{25.25}\)
\(T=\frac{1.2.3....24}{2.3.4...25}.\frac{3.4.5....26}{2.3.4....25}=\frac{1}{25}.\frac{26}{2}=\frac{13}{25}\)
\(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)...\left(1+\frac{1}{99}\right)=\frac{3}{2}.\frac{4}{3}...\frac{100}{99}=\frac{100}{2}=50\)
= \(\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot\cdot\cdot\cdot\frac{99}{98}\cdot\frac{100}{99}=\frac{3.4.5....99.100}{2.3.4....98.99}=\frac{100}{2}=50\)
=\(\frac{3}{2^2}x\frac{8}{3^2}x...x\frac{624}{25^2}\)
=\(\frac{1.3x2.4x...x624}{2^2x3^2x...x25^2}\)
=13/25
= \(\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\cdot\cdot\frac{19}{20}=\frac{1}{20}\)
=\(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{19}{20}\)
= đến đây bn xem trong thống kê hỏi đáp nhé
= :))
de ma ! Ne :
1 +1/2 =3/2 ; 1+2/3 = 4/3 ; ... ;1+1/10 =11/10.
Vay ta co : 3x4x5x6x7x8x9x10x11/2x3x4x5x6x7x8x9x10=11/2
vay thui !
\(\left(1+\frac{1}{100}\right).\left(1+\frac{1}{99}\right)............\left(1+\frac{1}{2}\right)\)
\(=\frac{101}{100}.\frac{100}{99}..............\frac{3}{2}\)
\(=\frac{101.100............3}{100.99...............2}\)
\(=\frac{101}{2}\)
\(=\frac{101}{100}.\frac{100}{989}.....\frac{3}{2}=\frac{101}{2}\)
=) \(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.....\frac{255}{256}.x=\frac{108}{7}\)
=) \(\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.....\frac{15.17}{16.16}.x=\frac{108}{7}\)
=) \(\frac{1.2.3.4.....15}{2.3.4.....16}.\frac{3.4.5.....17}{2.3.4.....16}.x=\frac{108}{7}\)
=) \(\frac{1}{16}.\frac{17}{2}.x=\frac{108}{7}\)=) \(\frac{17}{32}.x=\frac{108}{7}\)=) \(x=\frac{108}{7}:\frac{17}{32}\)
=) \(x=\frac{3456}{119}\)
(1+1/2000). ................. .(1+1/2013)
=2001/2000.2002/2001.2003/2002. .............. .2014/2013
=2013/2000
\(\left(1+\frac{1}{2000}\right)\cdot\left(1+\frac{1}{2001}\right)\cdot\left(1+\frac{1}{2002}\right)\cdot...\cdot\) \(\left(\frac{1}{2013}\right)\)
\(=\frac{2001}{2000}\cdot\frac{2002}{2001}\cdot\frac{2003}{2002}\cdot...\cdot\frac{2014}{2013}\)
\(=\frac{2001\cdot2002\cdot2003\cdot....\cdot2014}{2000\cdot2001\cdot2002\cdot...\cdot2013}\)
\(=\frac{2014}{2000}\)