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Cách 1 ở tất cả các câu: Tính bình thường như đề cho
a) Cách 2: \(\frac{5}{7}\times\frac{3}{4}+\frac{5}{7}\times\frac{1}{2}\)
b) Cách 2: \(\frac{13}{21}\times\left(\frac{5}{7}+\frac{2}{7}\right)\)
c) Cách 2: \(\frac{2}{5}\times\frac{1}{2}+\frac{2}{5}\times\frac{1}{3}\)
d) Cách 2: \(\frac{17}{21}\times\left(5+\frac{2}{5}\right)\)
a:\(=\left(\dfrac{3}{4}+\dfrac{2}{4}\right):\dfrac{3}{5}=\dfrac{5}{4}\cdot\dfrac{5}{3}=\dfrac{25}{12}\)
b: \(=\left(\dfrac{5}{6}-\dfrac{3}{6}\right):\dfrac{3}{2}=\dfrac{1}{3}\cdot\dfrac{2}{3}=\dfrac{2}{9}\)
a) C1
\(\dfrac{1}{8}\times\dfrac{5}{6}+\dfrac{5}{6}\times\dfrac{2}{3}=\dfrac{5}{6}\times\left(\dfrac{1}{8}+\dfrac{2}{3}\right)=\dfrac{5}{6}\times\dfrac{19}{24}=\dfrac{95}{144}\)
C2
\(\dfrac{1}{8}\times\dfrac{5}{6}+\dfrac{5}{6}\times\dfrac{2}{3}=\dfrac{5}{48}+\dfrac{10}{18}=\dfrac{95}{144}\)
b) C1
\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{3}{4}\times\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{3}{4}\times\dfrac{9}{10}=\dfrac{27}{40}\)
C2
\(\dfrac{7}{5}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{3}{4}=\dfrac{21}{20}-\dfrac{3}{8}=\dfrac{27}{40}\)
c) C1
\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\dfrac{35}{24}\times\dfrac{2}{3}=\dfrac{35}{36}\)
C2
\(\left(\dfrac{5}{6}+\dfrac{5}{8}\right)\times\dfrac{2}{3}=\left(\dfrac{5}{6}\times\dfrac{2}{3}\right)+\left(\dfrac{5}{8}\times\dfrac{2}{3}\right)=\dfrac{5}{9}+\dfrac{5}{12}=\dfrac{35}{36}\)
( 1/2 + 1/3 ) x 2/5
c1 = 5/6 x 2/5 = 1/3
c2 = 1/2 x 2/5 + 1/3 x 2/5
= 1/5 + 2/15
= 1/3
3/5 x 17/21 x 2/5
c1 := 17/35 x 2/5 = 34/175
c2 : = (3/5 x 2/5) x 17/21
= 6/25 x 17/21
= 34/175?
( 1/3 - 1/5 ) x 1/2
c1 : = 2/15 x 1/2
= 1/15
c2 : = 1/3 x 1/2 - 1/5 x 1/2
= 1/6 - 1/10
= 1/15
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: =17/21(3/5+2/5)=17/21
Chọn đáp án đúng:
A 3\5-1\5=2\10 B 15\7-6\7=8\7 C 18\21-5\7=1\7 D 17\18-1\6=7\9
a: \(=\dfrac{3}{22}\cdot22\cdot\dfrac{3}{11}=3\cdot\dfrac{3}{11}=\dfrac{9}{11}\)
b: \(=\dfrac{5}{6}\cdot\dfrac{2}{5}=\dfrac{1}{3}\)
c: \(=\dfrac{17}{21}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{17}{21}\)
a) C1 : \(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}=\left(\frac{3}{6}+\frac{2}{6}\right)\times\frac{2}{5}\)
\(=\frac{5}{6}\times\frac{2}{5}\)
\(=\frac{10}{30}=\frac{1}{3}\)
C2 : \(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}=\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}\)
\(=\frac{1}{5}+\frac{2}{15}\)
\(=\frac{3}{15}+\frac{2}{15}\)
\(=\frac{5}{15}=\frac{1}{3}\)
b) C1 : \(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{35}+\frac{34}{105}\)
\(=\frac{51}{105}+\frac{34}{105}\)
\(=\frac{85}{105}=\frac{17}{21}\)
C2 : \(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{21}\times\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=\frac{17}{21}\times1=\frac{17}{21}\)
Cảm ơn Vũ Huyền nhé