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\(N=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{19\cdot20}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{19}-\dfrac{1}{20}=\dfrac{19}{20}\)
Chẳng ai quan tâm tới câu hỏi của tui. Buồn quá. Buồn không còn gì để tả. À mà có văn đâu mà tả? :))))
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+....+\dfrac{1}{19}-\dfrac{1}{20}=\dfrac{19}{20}\)
A=\(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{15}+...+\dfrac{1}{380}\)
=\(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{3.5}+.....+\dfrac{1}{19.20}\)
=\(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{1}{5}+....+\dfrac{1}{19}-\dfrac{1}{20}\)
=\(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{20}=\dfrac{30}{60}-\dfrac{20}{60}-\dfrac{3}{60}=\dfrac{7}{60}\)
\(A=\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+...+\frac{1}{380}=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+...+\frac{1}{19.20}\)
=> \(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{20}=\frac{1}{5}-\frac{1}{20}\)
=> \(A=\frac{3}{20}\)
A = 1/30 + 1/42 + 1/56 + 1/72 +....+ 1/380
A = 1/5x6 + 1/6x7 + 1/7x8 + 1/8x9 +.....+1/19x20
A = 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/8 + 1/8 - 1/9 +......+ 1/19 - 1/20
A = 1/5 - 1/20 = 3/20
\(\dfrac{1}{6}x+\dfrac{1}{12}x+\dfrac{1}{20}x+...+\dfrac{1}{380}=9\)
\(x\left(\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{380}\right)=9\)
\(x\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{19.20}\right)=9\)
\(x\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{19}-\dfrac{1}{20}\right)=9\)
\(x\left(\dfrac{1}{2}-\dfrac{1}{20}\right)=9\)
\(x.\dfrac{9}{20}=9\)
\(x=9:\dfrac{9}{20}\)
\(x=20\)
Vậy \(x=20\)
a) 1/1x5 + ... + 1/21x25
= 4 x (1-1/5 + 1/5 - 1/9 + ... + 1/21 - 1/25)
= 1/4 x (1 - 1/25)
= 1/4 x 24/25
= 6/25