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Câu hỏi của Thd - Toán lớp 5 - Học trực tuyến OLM
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\(\dfrac{7}{8}-\dfrac{7}{16}-\dfrac{11}{32}=\dfrac{7.4}{8.4}-\dfrac{7.2}{16.2}-\dfrac{11}{32}=\dfrac{28}{32}-\dfrac{14}{32}-\dfrac{11}{32}=\dfrac{28-14-11}{32}=\dfrac{3}{32}\)
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
=(20+1)+(2+19)+...+(10+11) có 10 cặp số
=21+21+..+21 Có 10 số hạng
=21 x 10
=210
\(\dfrac{41}{36}:\dfrac{5}{12}=\dfrac{41}{36}\times\dfrac{12}{5}=\dfrac{492}{180}=\dfrac{41}{15}\\ 8:\dfrac{16}{17}=\dfrac{8}{1}\times\dfrac{17}{16}=\dfrac{136}{16}=\dfrac{17}{2}\\ \dfrac{16}{13}:8=\dfrac{16}{13}\times\dfrac{1}{8}=\dfrac{2}{13}\)
\(\)\(\dfrac{41}{36}\) : \(\dfrac{5}{12}\) = \(\dfrac{41}{36}\) x \(\dfrac{12}{5}\) =\(\dfrac{41}{15}\)
8 : \(\dfrac{16}{17}\) = 8 x \(\dfrac{17}{16}\) =\(\dfrac{17}{2}\)
\(\dfrac{16}{13}\) : 8 = \(\dfrac{16}{13}\) x \(\dfrac{1}{8}\) =\(\dfrac{2}{13}\)
58 x 42 + 32 x 8 + 5 x 16
= 116 x 21 + 16 x 16 + 5 x 16
= 116 x 21 + 16(16 + 5)
= 116 x 21 + 16 x 21
= 21 x ( 116 + 16 )
= 21x 132
= 2772
58*42+32*8+5*16
=58*42+2*16*8+5*16
=58*21*2+16*(2*8+5)
=58*21*2+16*21
=21*(58*2+16)
=21*(116+16)
=21*132
=2772
a,
250.12-(242+302.2)
=3000-(242+604)
=3000-846
=2154
b,
3/5+6/11+7/13+2/5+16/11+19/13
=(3/5+2/5)+(6/11+16/11)+(7/13+19/13)
=1+2+2
=5.
K mình nhé!
(100/7+100/9+100/11):(1/7+1/9+1/11)
=100.(1/7+1/9+1/11):(1/7+1/9+1/11)
=(100:1)(1/7+1/9+1/11)
=100.239/693
=23900/693
\(\left(\frac{100}{7}+\frac{100}{9}+\frac{100}{11}\right)\div\left(\frac{1}{7}+\frac{1}{9}+\frac{1}{11}\right)\)
= \(100\times\left(\frac{1}{7}+\frac{1}{9}+\frac{1}{11}\right)\div\left(\frac{1}{7}+\frac{1}{9}+\frac{1}{11}\right)\)
= \(100\)
(19+1)+(18+2)+(17+3)+(16+4)+(15+5)+(14+6)+(13+7)+(12+8)+(11+9)+20)+10
=20+20+20+20+20+20+20+20+20+20=(20*10)+10
=210
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
=(1+19)+(2+18)+(3+17)+(4+16)+(5+15)+(6+14)+(7+13)+(8+12)+(9+11)+(10+20)
=20+20+20+20+20+20+20+20+20+30
=(20 x 9) + 30
=180 + 30
=210
tk nha
\(=\dfrac{28}{32}-\dfrac{14}{32}-\dfrac{11}{32}=\dfrac{3}{32}\)
28/32 - 14/32 - 11/32 = 3 /32