Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(3\times\frac{6}{11}+\frac{6}{11}\times5+2\times\frac{6}{11}\text{ }\)
\(=\frac{6}{11}\times\left(3+5+2\right)\)
\(=\frac{6}{11}\times10\)
\(=\frac{60}{11}\)
\(=\dfrac{5}{11}-\dfrac{3}{5}+\dfrac{6}{11}=1-\dfrac{3}{5}=\dfrac{2}{5}\)
a, (6/11+5/11)x3/17
c1:=1x3/17
=3/17
c2:=6/11x3/17+5/11x3/17
=18/197+15/187
=33/187
=3/17
b,3/5x7/9-3/5x2/9
c1:=21/45-6/45
=15/45
=1/3
c2:=3/5x(7/9-2/9)
=3/5x5/9
=1/3
c,( 6/7-4/7):2/5
c1:=2/7:2/5
=2/7x5/2
=5/7
c2,6/7:2/5-4/7:2/5
=6/7x5/2-4/7x5/2
=15/7-10/7
=5/7
d,8/15:2/11+7/15:2/11
c1:=(8/15+7/15):2/11
=1x11/2
=11/2
c2:=8/15x11/2+7/15x11/2
=88/30+77/30
=165/30
=11/2
a) (\(\frac{6}{11}\) + \(\frac{5}{11}\)) x \(\frac{3}{17}\)= \(\frac{11}{11}\) x \(\frac{3}{17}\)= \(1\) x\(\frac{3}{17}\)= \(\frac{3}{17}\)
b) \(\frac{3}{5}\)x\(\frac{7}{9}\)- \(\frac{3}{5}\)x \(\frac{2}{9}\) = \(\frac{3}{5}\)x (\(\frac{7}{9}\)- \(\frac{2}{9}\))= \(\frac{3}{5}\) x \(\frac{5}{9}\)= \(\frac{3}{9}\)
c) (\(\frac{6}{7}\)- \(\frac{4}{7}\)) : \(\frac{2}{5}\)= \(\frac{2}{7}\) x \(\frac{5}{2}\)= \(\frac{5}{7}\)
d) \(\frac{8}{15}\) : \(\frac{2}{11}\) + \(\frac{7}{15}\): \(\frac{2}{11}\)= ( \(\frac{8}{15}\)+ \(\frac{7}{15}\)) x \(\frac{11}{2}\)= 1 x \(\frac{11}{2}\)= \(\frac{11}{2}\)
Chúc học tốt nha!
(6:3/5-7/6×6/7) : (21/5×10/11+57/11)
=(10-1):(42/11+57/11)
=9:9
=1
(6:3/5-7/6x6/7):(21/5x10/11+57/11)
= (10-1):(42/11+57/11)
=9:9
=1
~~~~ Hoc tot ~~~~~
nhiều thế ren giải được ma bik giải xng rồi có dc chi hông?
\(\left(\dfrac{6}{11}+\dfrac{5}{11}\right)\times\dfrac{3}{7}=\dfrac{11}{11}\times\dfrac{3}{7}=1\times\dfrac{3}{7}=\dfrac{3}{7}\)
\(\dfrac{3}{5}\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{1}{3}\)
\(C1:\left(\frac{6}{11}+\frac{5}{11}\right).\frac{3}{7}=1.\frac{3}{7}=\frac{3}{7}\)
\(C2:\left(\frac{6}{11}+\frac{5}{11}\right).\frac{3}{7}=\frac{6}{11}.\frac{3}{7}+\frac{5}{11}.\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{3}{7}\)
\(C1:\left(\frac{6}{7}-\frac{4}{7}\right):\frac{2}{5}=\frac{2}{7}:\frac{2}{5}=\frac{5}{7}\)
\(C2:\left(\frac{6}{7}-\frac{4}{7}\right):\frac{2}{5}=\frac{6}{7}:\frac{2}{5}-\frac{4}{7}:\frac{2}{5}=\frac{15}{7}-\frac{10}{7}=\frac{5}{7}\)