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7/8 x 1/4 + 7/8 x 2/4 + 7/8
=7/8 x\(\left(\dfrac{1}{4}+\dfrac{2}{4}\right)\) + 7/8
=7/8 x 3/4 + 7/8
=7/8 x \(\left(\dfrac{3}{4}+1\right)\)
=7/8 x 7/4
=49/32
Sure=)
Simple task:)
Tính bằng cách thuận tiện nhất :
3/7 + 1/8 + 4/7 + 7/8
a. 2
b. 1 + 1
c. 2 + 1
d. ( 3/7 + 1/8 ) + ( 4/7 + 7/8 )
e. 3
g. 1 + 2
h. ( 3/7 + 4/7 ) + ( 1/8 + 7/8 )
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
\(\dfrac{3}{5}+\dfrac{7}{8}=\dfrac{3.8+7.5}{5.8}=\dfrac{24+35}{40}=\dfrac{59}{40}\\ 2+\dfrac{3}{4}=\dfrac{2.4+3}{4}=\dfrac{11}{4}\\ 1-\dfrac{3}{4}=\dfrac{4-3}{4}=\dfrac{1}{4}\\\dfrac{6}{8}+7=\dfrac{6+7.8}{8}=\dfrac{62}{8}=\dfrac{31}{4}\\ \dfrac{35}{9}-2=\dfrac{35-2.9}{9}=\dfrac{17}{9}\)
Giải thích : \(\left(.\right)\) dấu chấm này là dấu nhân nhé
4 × 2 7 = 8 7 8 7 : 2 7 = 8 7 × 7 2 = 4 8 7 : 4 = 2 7 2 7 × 4 = 8 7