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4 tháng 2 2018

\(\frac{1}{90}-\frac{1}{72}-\frac{1}{56}-\frac{1}{42}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}\)

\(=\)\(\frac{1}{9.10}-\frac{1}{8.9}-\frac{1}{7.8}-\frac{1}{6.7}-\frac{1}{5.6}-\frac{1}{4.5}-\frac{1}{3.4}-\frac{1}{2.4}-\frac{1}{1.2}\)

\(=\)\(\left(\frac{1}{9}-\frac{1}{10}\right)-\left(\frac{1}{8}-\frac{1}{9}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{4}-\frac{1}{5}\right)-\left(\frac{1}{3}-\frac{1}{4}\right)\)\(-\left(\frac{1}{2}-\frac{1}{3}\right)-\left(\frac{1}{1}-\frac{1}{2}\right)\)

\(=\)\(\frac{1}{9}-\frac{1}{10}-\frac{1}{8}+\frac{1}{9}-\frac{1}{7}+\frac{1}{8}-\frac{1}{6}+\frac{1}{7}-\frac{1}{5}+\frac{1}{6}-\frac{1}{4}+\frac{1}{5}-\frac{1}{3}+\frac{1}{4}-\frac{1}{2}+\frac{1}{3}-\frac{1}{1}+\frac{1}{2}\)

\(=\)\(\frac{2}{9}-\frac{1}{10}-1\)

\(=\)\(\frac{20}{90}-\frac{9}{90}-\frac{90}{90}\)

\(=\)\(\frac{-79}{90}\)

4 tháng 2 2018

cảm ơn bạn

27 tháng 2 2020

\(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)

\(=\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)

\(=\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(=\frac{1}{4}-\frac{1}{10}=\frac{6}{40}\)

25 tháng 11 2015

1-1/2+1/2-1/3+1/3+1/4-1/4+1/5-1/5+1/6-1/6+1/7-1/7+1/8-1/8+1/9-1/9+1/10-(1-1/3+1/3-3/5+3/5-4/7+5/9-5/9+6/11-6/11-7/13)=1+1/10-1+7/13=83/130

https://olm.vn/hoi-dap/detail/7709875367.html

2 tháng 3 2017

ta co

\(\frac{1}{1.2}+\frac{1}{2.3}+....+\frac{1}{9.10}>\frac{1}{2.2}+\frac{1}{3.3}+....+\frac{1}{10.10}\)

ma ve trai =\(1-\frac{1}{10}\)

nen ve phai <1

2 tháng 3 2017

D=1/1.2+1/2.3+1/4.5+1/5.6+1/6.7+1/7.8+1/8.9+1/9.10

=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10

=1+0+0+0+...+0-1/10=1-1/10=9/10

ta có ; 1/2+1/32+...+1/20172<1/1.2+1/2.3+1/3.4+.....+1/2016.2017=1-1/2+1/2-1/3+...+1/2016-1/2017=1+0+0+0+...+0-1/2017

=1-1/2017<1

22 tháng 3 2018

ta có: 1/2=1/1x2

          1/6=1/2x3

           1/12=1/3x4

             1/20=1/4x5

             1/30=1/5x6

                1/42=1/6x7

                 1/56=1/7x8

              1/72=1/8x9

               1/90=1/9x10

                1/110=1/10x11

              tiếp theo bn tiếp tục nhé

22 tháng 3 2018

1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90+1/110

=1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8+1/8x9+1/9x10+1/10x1

=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10+1/10-1/11

=1-1/11

=10/11

14 tháng 4 2021

−190−172−156−142−130−120−112−16−12

=−190−(12+16+112+120+130+142+156+172)

=−190−(11.2+12.3+13.4+14.5+15.6+16.7+17.8+18.9)

=−190−(1−12+12−13+13−14+14−15+15−16+16−17+17−18+18−19)

=−190−(1−19)

=−190−89

3 tháng 8 2016

\(\frac{-1}{90}-\frac{1}{72}-\frac{1}{56}-\frac{1}{42}-\frac{1}{30}-\frac{1}{20}-\frac{1}{12}-\frac{1}{6}-\frac{1}{2}\)

\(-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\right)\)

=\(-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\right)\)

=\(-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)

=\(-\left(1-\frac{1}{10}\right)=-\left(\frac{9}{10}\right)=-\frac{9}{10}\)

3 tháng 8 2016

\(\frac{-1}{90}-\frac{-1}{72}-\frac{-1}{56}-\frac{-1}{42}-\frac{-1}{30}-\frac{-1}{20}-\frac{-1}{12}-\frac{-1}{6}-\frac{-1}{2}\)

\(=\frac{-1}{10.9}-\frac{-1}{9.8}-\frac{-1}{8.7}-\frac{-1}{7.6}-\frac{-1}{6.5}-\frac{-1}{5.4}-\frac{-1}{4.3}-\frac{-1}{3.2}-\frac{-1}{2.1}\)

17 tháng 4 2017

1/100 - 1/90 - 1/72 - 1/56 - 1/42 - 1/30 - 1/20 - 1/12 - 1/6 - 1/2 = -0,833

20 tháng 3 2018

= -79/90