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\(M=\frac{1.2}{2}+\frac{2.3}{2}+\frac{3.4}{2}+\frac{4.5}{2}+...+\frac{48.49}{2}+\frac{49.50}{2}=\frac{1.2+2.3+3.4+4.5+...+48.49+49.50}{2}\)
Dặt\(A=1.2+2.3+3.4+...+48.49+49.50\Rightarrow3A=1.2.3+2.3.3+3.4.3+...+48.49.3+49.50.3\)
\(=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+48.49.\left(50-47\right)+49.50.\left(51-48\right)\)
\(=1.2.3+\left(2.3.4-1.2.3\right)+\left(3.4.5-2.3.4\right)+...+\left(48.49.50-47.48.49\right)+\left(49.50.51-48.49.50\right)\)
\(=\left(1.2.3+2.3.4+3.4.5+...+48.49.50+49.50.51\right)-\left(1.2.3+2.3.4+...+47.48.49+48.49.50\right)\)
\(\Rightarrow3A=49.50.51=124950\Rightarrow A=41650\)
Mà\(M=\frac{A}{2}\)
\(\Rightarrow M=\frac{41650}{2}=20825\)
Vậy M=20825
Mk đặt =M cho ngắn gọn
4 * ( x - 3 ) = 72 - 110
4 * ( x - 3 ) = 48
( x - 3 ) = 48 / 4
( x - 3 ) = 12
x = 12 + 3
x = 15
mk nhanh nhất nè k mk đi
TBR , ta có :
\((x-\frac{1}{3})^2\)\(-\frac{1}{9}\)\(=\frac{5}{3}\)
\(\Rightarrow(x-\frac{1}{3})^2=\frac{5}{3}+\frac{1}{9}=\frac{16}{9}\)
\(\Rightarrow(x-\frac{1}{3})^2=(\frac{4}{9})^2\)
\(\Rightarrow x-\frac{1}{3}=\frac{4}{9}\)
\(\Rightarrow x=\frac{4}{9}+\frac{1}{3}\)
\(\Rightarrow x=\frac{7}{9}\)
K cho mình nha
( x -1/3 )^2 - 1/9 = 5/3
( x -1/3 )^2 = 5/3 + 1/9
( x - 1/3 )^2 = 15/9 + 1/9
( x - 1/3 )^2 = 16/9
( x - 1/3 ) = -4/3 hoặc x -1/3 = 4/3
=> x = -4/3 + 1/3 hoặc x = 4/3 + 1/3
=> x = -3/3 = -1 hoặc x = 5/3
Vậy x = -1 hoặc x = 5/3
Chúc học giỏi !!!
1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 . ..... . 1/14.15
= 1/5 + 1/6 - 1/6 + 1/7 + 1/7 - 1/8 + 1/9 - ..... + 1/14 - 1/15
= 1/5 - 1/15
= 2/15
Tính giá trị biểu thức :
( 1 + 2 + 3 + .... + 100 ) . ( 12 + 22 + 32 + ..... + 102 ) . ( 65 . 111 -13 . 15 . 37 )
= ( 1 + 2 + 3 + .... + 100 ) . ( 12 + 22 + 32 + ..... + 102 ) . (7215 - 7215)
= ( 1 + 2 + 3 + .... + 100 ) . ( 12 + 22 + 32 + ..... + 102 ) . 0
= 0
Vậy kết quả của giá trị biểu thức trên là 0
\(B=2B-B=2+2^2+2^3+2^4+...+2^{11}-\left(1+2^2+2^3+...+2^{10}\right)=2^{11}-1=2048-1=2047\)
\(B=\left(\frac{1}{4}-1\right)\cdot\left(\frac{1}{9}-1\right).....\left(\frac{1}{81}-1\right)\cdot\left(\frac{1}{100}-1\right)\)
\(B=\frac{-3}{4}\cdot\frac{-8}{9}....\frac{-80}{81}\cdot\frac{-99}{100}\)
\(B=-\left(\frac{3}{4}\cdot\frac{8}{9}\cdot\cdot\cdot\cdot\frac{99}{100}\right)\)
\(B=-\left(\frac{3\cdot8\cdot15\cdot24\cdot....\cdot63\cdot80\cdot99}{2^2\cdot3^2\cdot4^2\cdot\cdot\cdot\cdot\cdot9^2\cdot10^2}\right)\)
\(B=-\left(\frac{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot\cdot\cdot\cdot8\cdot10\cdot9\cdot11}{2^2\cdot3^2\cdot4^2\cdot\cdot\cdot\cdot9^2\cdot10^2}\right)\)
\(B=-\frac{11}{2\cdot10}\)
\(B=\frac{-11}{20}\)
\(B=\left(\frac{1}{4}-1\right).\left(\frac{1}{9}-1\right)...\left(\frac{1}{100}-1\right)\)
\(B=\frac{-3}{2^2}.\frac{-8}{3^2}...\frac{-99}{10^2}\)
\(B=-\left(\frac{3}{2^2}.\frac{8}{3^2}...\frac{99}{10^2}\right)\)(có 9 thừa số, mỗi thừa số là âm nên kết quả là âm)
\(B=-\left(\frac{1.3}{2.2}.\frac{2.4}{3.3}...\frac{9.11}{10.10}\right)\)
\(B=-\left(\frac{1.2...9}{2.3...10}.\frac{3.4...11}{2.3...10}\right)\)
\(B=-\left(\frac{1}{10}.\frac{11}{2}\right)\)
\(B=-\frac{11}{20}\)
\(A=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}\)
\(\frac{1}{2}A=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}\)
\(\frac{1}{2}A=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
\(\frac{1}{2}A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{8}-\frac{1}{9}\)
\(\frac{1}{2}A=\frac{1}{2}-\frac{1}{9}\)
\(\frac{1}{2}A=\frac{7}{18}\)
\(A=\frac{7}{18}x2\)
\(A=\frac{7}{9}\)
3628800.
10! = 3628800