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a, =25- 62-25 +12
= (25-25)+12-62
= -50
b, = -24 -68+24 + 2. (-60)
= (-24+24)-68 + -120
= -188
c,
![](https://rs.olm.vn/images/avt/0.png?1311)
\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)
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Bài 1
Số nguyên âm lớn nhất có 4 chữ số :-1000
Số nguyên dương nhỏ nhất có ba chữ số :100
Vậy tổng của chúng là -1000+100=-900
Bài 2
a, (-23)-(+3).(-11)
= (-23) - (-33)
= 10
c,85.(27-35)-35.(27-85)
= 85.27 - 85.35 - 35.27 - 35.85
=(85.27 - 35.27) - (85.35 - 35.85)
=27. (85 - 35) - 0
= 27. 50
=1350
b,(-8)^2 . 69 + 69 . (-6)^2
= 69 . [(-8)^2 + (-6)^2]
=69 . [64 + 36]
=69.100
=6900
Bài 3
a,27 + 4x = 34 - (-13)
27+4x=47
4x=47-27
4x=20
x=20/4
x=5 Vậy x=5
b,3x-9-15=27
3x-9=27+15
3x-9=42
3x=42+9
3x=51
=> x=51/3
x=17 Vậy x=17
c,12-7(x-1)=-9
7(x-1)=12-(-9)
7(x-1)=21
x-1=21/7
x-1 = 3 Vậy x=3
Bài 4
1-2+3-4........+99-100-101
=(1-2)+(3-4).....+(99-100)-101
=(-1)+(-1)+.....+(-1) -101
Từ 1 đến 100 có 50 cặp
=> (-1)+(-1)+...+(-1) -101
=-50 -101
=-151
K CHO MINK NKA
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(-75+\left(-325\right)+\left|-45\right|-\left(-125\right)\)
\(=-75-325+45+125\)
\(=\left(45+125\right)-\left(75+325\right)\)
\(=170-400\)
\(=-230\)
b) \(62+\left|128\right|-\left|-155\right|-\left|70\right|\)
\(=62+128-155-70\)
\(\Leftrightarrow190-225\)
\(=-35\)
c) \(815+\left[95+\left(-815\right)+\left(-45\right)\right]\)
\(=815+95-815-45\)
\(=\left(815-815\right)+\left(95-45\right)\)
\(=0+50\)
\(=50\)
d) \(5+\left(-7\right)+9+\left(-11\right)+...+25+\left(-27\right)\)
\(=\left(5-7\right)+\left(9-11\right)+...+\left(25-27\right)\)
\(=-2-2-...-2\)
\(=-2.11\)
\(=-22\)
e) \(34+35+36+37-24-25-26-27\)
\(=\left(34-24\right)+\left(35-25\right)+\left(36-26\right)+\left(37-27\right)\)
\(=10+10+10+10\)
\(=40\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1. (-34)+24+(-7)+27=-10+20=10
2.99+(-100)+101=(99+101)+(-100)=200-100=100
3.(-75)+69+(-25)+131=(69+131)-(75+25)=200-100=100
1) \(\left(-34\right)+24+\left(-7\right)+27\)
\(=-34+24-7+27\)
\(=-\left(34-24\right)-7+27\)
\(=-10-7+27\)
\(=-\left(10+7\right)+27\)
\(=-17+27\)
\(=27-17\)
\(=10\)
2) \(99+\left(-100\right)+101\)
\(=99-100+101\)
\(=-100+99+101\)
\(=-\left(100-99\right)+101\)
\(=-1+101\)
\(=101-1\)
\(=100\)
3) \(\left(-75\right)+69+\left(-25\right)+131\)
\(=-75+69-25+131\)
\(=-\left(75-69\right)-25+131\)
\(=-6-25+131\)
\(=-\left(6+25\right)+131\)
\(=-31+131\)
\(=131-31\)
\(=100\)