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M = \(15.\left(\frac{1}{15.16}+\frac{1}{16.17}+...+\frac{1}{19.20}\right)\)
= \(15.\left(\frac{1}{15}-\frac{1}{16}+\frac{1}{16}-\frac{1}{17}+...+\frac{1}{19}-\frac{1}{20}\right)\)
= \(15.\left(\frac{1}{15}-\frac{1}{20}\right)\)
= \(15.\frac{1}{60}\)= \(\frac{1}{4}\)\(< \frac{1}{3}\)
(=) \(M< \frac{1}{3}\)\(\left(đpcm\right)\)
Ta có: \(M=\frac{15}{15.16}+\frac{15}{16.17}+\frac{15}{17.18}+\frac{15}{18.19}+\frac{15}{19.20}\)
\(\Rightarrow M=15.\left(\frac{1}{15.16}+\frac{1}{16.17}+\frac{1}{17.18}+\frac{1}{18.19}+\frac{1}{19.20}\right)\)
\(\Rightarrow M=15.\left(\frac{1}{15}-\frac{1}{16}+\frac{1}{16}-\frac{1}{17}+\frac{1}{17}-\frac{1}{18}+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\right)\)
\(\Rightarrow M=15.\left(\frac{1}{15}-\frac{1}{20}\right)\)
\(\Rightarrow M=15.\frac{1}{60}=\frac{1}{4}\)
Ta thấy: \(\frac{1}{4}< \frac{1}{3}\Rightarrow M< \frac{1}{3}\)
Vậy \(M< \frac{1}{3}\)
Chúc bạn học tốt!
Gọi \(S=\frac{15}{15\cdot16}+\frac{15}{16\cdot17}+..+\frac{15}{19\cdot20}\)
\(\Leftrightarrow S=1-\frac{15}{16}+\frac{15}{16}-\frac{15}{17}+...+\frac{15}{19}-\frac{15}{20}\)
\(\Leftrightarrow S=1-\frac{15}{20}=\frac{1}{4}<\frac{1}{3}\)
Vậy S< \(\frac{1}{3}\)
--------------------Good luck------------------------
\(\text{15.(-176)+15.76+100.15}\)
\(=15.\left(-176+76+100\right)\)
\(=15.0\)
\(=0\)
\((-18)+(-31)+98+\left|-18\right|+(-69)\)
\(=(-18)+(-31)+98+18+(-69)\)
\(=(-18)+18+(-31)+(-69)+98\)
\(=0+(-100)+98=-2\)
Ta có :
\(15=3.5\)
\(16=2^4\)
\(18=2.3^2\)
\(\Rightarrow BCNN\left(15;16;18\right)=2^4.3^2.5=720\)
\(\Rightarrow BC\left(15;16;18\right)=B\left(720\right)=\left\{0;720;1440;...\right\}\)
Ta có: 15= 3.5
16= 24
18= 2.32
---> BCNN (15;16;18)= 24.32.5= 720
----> BC (15;16;18) E {0;720; 1440;2160;2880;...}
_Học tốt_