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a,
\(y:\dfrac{2}{5}=12\)
\(y=12\times\dfrac{2}{5}\)
\(y=\dfrac{24}{5}=4,8\)
b,
\(\dfrac{11}{10}+\dfrac{4}{5}\times\dfrac{3}{4}=\dfrac{11}{10}+\dfrac{12}{20}=\dfrac{22}{20}+\dfrac{12}{20}=\dfrac{34}{20}=\dfrac{17}{10}\)
bài 1 :
\(\frac{5}{12}\) + \(\frac{1}{3}\) = \(\frac{5}{12}\) + \(\frac{4}{12}\) = \(\frac{5+4}{12}\) = \(\frac{9}{12}\) = \(\frac{3}{4}\)
1 - \(\frac{3}{4}\) = \(\frac{4}{4}\) - \(\frac{3}{4}\) = \(\frac{4-3}{4}\) = \(\frac{1}{4}\)
2 x \(\frac{3}{11}\) = \(\frac{2x3}{11}\) = \(\frac{6}{11}\)
\(\frac{8}{7}\): 4 = \(\frac{8}{7x4}\) = \(\frac{8}{28}\) = \(\frac{2}{7}\)
bài 2 :
\(\frac{2}{5}\) : y = \(\frac{1}{3}\)
y = \(\frac{2}{5}\) : \(\frac{1}{3}\)
y = \(\frac{6}{5}\)
y : \(\frac{7}{11}\) = 22
y = 22 x \(\frac{7}{11}\)
y = 14
ai thấy đúng tk nha
Câu 10:
\(a,y\times7+y\times3=70\\ \Rightarrow y\times\left(7+3\right)=70\\ \Rightarrow y\times10=70\\ \Rightarrow y=7\\ b,18:y+12:y=3\\ \Rightarrow\left(18+12\right):y=3\\ \Rightarrow30:y=3\\ \Rightarrow y=10\)
câu 11:
\(a,9\times365+2\times365-365=\left(9+2-1\right)\times365=10\times365=3650\\ b,108:9-18:9=\left(108-18\right):9=90:9=10\\ c,43\times95+4\times43+43=43\times\left(95+4+1\right)=43\times100=4300\)
A \(\frac{2}{3}+y=\frac{11}{12}.5\)
\(\Rightarrow\frac{2}{3}+y=\frac{55}{12}\)
\(\Rightarrow y=\frac{55}{12}-\frac{2}{3}\)
\(\Rightarrow y=\frac{55}{12}-\frac{8}{12}\)
\(\Rightarrow y=\frac{47}{12}\)
`y xx 1/2 + y xx 2/3 + y = 11/5`
`<=> y xx (1/2 + 2/3 +1)=11/5`
`<=> y xx 11/6 = 11/5`
`<=> y = 6/5`.
Vậy `y = 6/5`
\(1)\frac{12}{7}\times \frac{7}{4}+\frac{35}{11}:\frac{245}{121}\)
\(=3+\frac{35}{11}\times \frac{121}{245}\)
\(=3+\frac{11}{7}\)
\(= 3\frac{1}{7}(=\frac{22}{7})\)
a) y : 4/11 x 3/5 = 27/4
y : 4/11 = 27/4 : 3/5
y : 4/11 = 45/4
y = 45/4 x 4/11
y = 45/11
b) y + 7/2 - 5/9 = 14/3
y + 7/2 = 14/3 + 5/9
y + 7/2 = 47/9
y = 47/9 - 7/2
y = 31/18
a) y : 4/11 x 3/5 = 27/4
y : 4/11 = 27/4 : 3/5
y : 4/11 = 45/4
y = 45/4 x 4/11
y = 45/11
b) y + 7/2 - 5/9 = 14/3
y + 7/2 = 14/3 + 5/9
y + 7/2 = 47/9
y = 47/9 - 7/2
y = 31/18
