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a.
31,5 – x = (18,6 – 12,3) : 3
31,5 - x = 2,1
x = 31,5 - 2,1
x = 29,4
b.
???
\(\frac{17,8.3,7-7,8.4,8+5,7.17,8-4,6.7,8}{11,2+12,3+13,4-12,6-11,5-10,4}\)
\(=\frac{17,8\left(3,7+5,7\right)-7,8\left(4,8+4,6\right)}{\left(13,4-12,6\right)+\left(12,3-11,5\right)+\left(11,2-10,4\right)}\)
\(=\frac{17,8.9,4-7,8.9,4}{0,8+0,8+0,8}\)
\(=119,1\)
a: \(\Leftrightarrow x\cdot12.3=123\)
=>x=10
b: \(\dfrac{3x-0.8}{x}+14.5=15\)
\(\Leftrightarrow\dfrac{3x-0.8}{x}=0.5\)
\(\Leftrightarrow3x-0.8=0.5x\)
=>2,5x=0,8
hay x=8/25
c: \(\Leftrightarrow12.5\cdot x=5.58-4.85=0.73\)
hay x=73/1250
a) Ta có: \(\left|4-5x\right|=24\)
\(\Leftrightarrow\left[{}\begin{matrix}-5x+4=24\\-5x+4=-24\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-5x=20\\-5x=-28\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=\dfrac{28}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{-4;\dfrac{28}{5}\right\}\)
b) Ta có: \(\left(8+x\right)\left(6-x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+8=0\\6-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=6\end{matrix}\right.\)
Vậy: \(x\in\left\{-8;6\right\}\)
a) \(\left|4-5x\right|=24\)
\(\Leftrightarrow\left[{}\begin{matrix}4-5x=24\\4-5x=-24\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=\dfrac{28}{5}\end{matrix}\right.\)
b) \(\left(8+x\right)\left(6-x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}8+x=0\\6-x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=6\end{matrix}\right.\)
Lời giải:
Cần bổ sung điều kiện $x$ là số nguyên.
a.
$2x+5\vdots x+1$
$\Rightarrow 2(x+1)+3\vdots x+1$
$\Rightarrow 3\vdots x+1$
$\Rightarrow x+1\in\left\{\pm 1; \pm 3\right\}$
$\Rightarrow x\in\left\{0; -2; 2; -4\right\}$
b.
$-x-5\vdots -x-1$
$\Rightarrow (-x-1)-4\vdots -x-1$
$\Rightarrow 4\vdots -x-1$
$\Rightarrow -x-1\in\left\{\pm 1; \pm 2; \pm 4\right\}$
$\Rightarrow x\in \left\{0; -2; 1; -3; 3; -5\right\}$
a: =>2x+2+3 chia hêt cho x+1
=>\(x+1\in\left\{1;-1;3;-3\right\}\)
=>\(x\in\left\{0;-2;2;-4\right\}\)
b: =>x+5 chia hết cho x+1
=>\(x+1\in\left\{1;-1;2;-2;4;-4\right\}\)
=>\(x\in\left\{0;-2;1;-3;3;-5\right\}\)
1) \(16,2\times3,7+5,7\times16,2-7,8\times4,8-4,6\times7,8\)
\(=16,2.\left(3,7\times5,7\right)-7,8.\left(4,8\times4,6\right)\)
\(=16,2.9,4-7,8.9,4\)
\(=9,4.\left(16,2-7,8\right)\)
\(=9,4.8,4=78,96\)
2) \(11,2+12,3+13,4-12,6-11,5-10,4\)
\(=\left(11,2-10,4\right)+\left(12,3-11,5\right)+\left(13,4-12,6\right)\)
\(=0,8+0,8+0,8\)
\(=0,8.3=2,4\)
1) 16,2×3,7+5,7×16,2−7,8×4,8−4,6×7,816,2×3,7+5,7×16,2−7,8×4,8−4,6×7,8
=16,2.(3,7×5,7)−7,8.(4,8×4,6)=16,2.(3,7×5,7)−7,8.(4,8×4,6)
=16,2.9,4−7,8.9,4=16,2.9,4−7,8.9,4
=9,4.(16,2−7,8)=9,4.(16,2−7,8)
=9,4.8,4=78,96=9,4.8,4=78,96
2) 11,2+12,3+13,4−12,6−11,5−10,411,2+12,3+13,4−12,6−11,5−10,4
=(11,2−10,4)+(12,3−11,5)+(13,4−12,6)=(11,2−10,4)+(12,3−11,5)+(13,4−12,6)
=0,8+0,8+0,8=0,8+0,8+0,8
=0,8.3=2,4
a) 31,5 - X = 2.1
X = 31,5 - 2,1
X = 29.4
b) X . 12,5 = 111
X = 111 : 12,5
X = 8.88
a)\(x=31,5-\left[\left(18,6-12,3\right):3\right]=31,5-2,1=29,4\)
b)\(x=\left[\left(32,6-10,4\right).5\right]=11112,5=8,88\)