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\(36\div\left[7.\left(x-3\right)+4\right]=6\)
\(\Rightarrow7.\left(x-3\right)+4=36\div6\)
\(\Rightarrow7.\left(x-3\right)+4=6\)
\(\Rightarrow7.\left(x-3\right)=6-4\)
\(\Rightarrow7.\left(x-3\right)=2\)
\(\Rightarrow x-3=2\div7\)
\(\Rightarrow x-3=\frac{2}{7}\)
\(\Rightarrow x=\frac{2}{7}+3\)
\(\Rightarrow x=\frac{23}{7}\)
\(36:\left[7.\left(x-3\right)+4\right]=6\)
\(7.\left(x-3\right)+4=36:6\)
\(7.\left(x-3\right)+4=6\)
\(7.\left(x-3\right)=6-4\)
\(7.\left(x-3\right)=2\)
\(x-3=2:7\)
\(x-3=\frac{2}{7}\)
\(x=\frac{2}{7}+3\)
\(x=\frac{23}{7}\)
12x-43=4.84:89
12x-43=32
12x =32+64(32))
12x =96
x= 96:12
x=8
k nha
(12x-43)=4.(84:83)
12x-64=4.8
12x-64=32
12x=32+64
12x=96
x=96/12
x=8
Ta có:
\(\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}.\left(2x+1\right)=5\)
\(\Rightarrow\frac{2}{3}-\frac{1}{3}x+\frac{1}{3}.\frac{3}{2}-x-\frac{1}{2}=5\)
\(\Rightarrow\frac{2}{3}-\left(\frac{1}{3}x+x\right)+\frac{1}{2}-\frac{1}{2}=5\)
\(\Rightarrow\frac{4}{3}x=\frac{2}{3}-5=-\frac{13}{3}\)
\(\Rightarrow x=-\frac{13}{3}:\frac{4}{3}=-\frac{13}{3}.\frac{3}{4}=-\frac{13}{4}\)
Vậy x=-13/4
\(\text{a/96-3(x+1)=42}\)
\(3\left(x+1\right)=54\)
\(x+1=54:3\)
\(x+1=18\)
\(\Rightarrow x=17\)
\(\text{b/2.x-18=20}\)
\(2x=38\)
\(x=38:2\)
\(x=19\)
\(\text{c/134-5.(x+4)=34}\)
\(5\left(x+4\right)=100\)
\(x+4=100:5\)
\(x+4=20\)
\(\Rightarrow x=16\)
học tốt
a) 96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54:3
x+1=18
x=18-1
Vậy x=17
b) 2x-18=20
2x=20+18
2x=38
x=38:2
x=19
Vậy x=19.
c) 134-5(x+4)=34
5(x+4)=134-34
5(x+4)=100
x+4=100:5
x+4=20
x=20-4
x=16
Vậy x=16.
a) 96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54:3
x+1=18
x=18-1
x=17
Vậy x=17
b)2.x-18=20
2.x =20+18
2.x =38
x =38:2
x =19
Vậy x=19
c)134-5.(x+4)=34
5.(x+4)=134-34
5.(x+4)=100
x+4 =100:5
x+4 =20
x =20-4
x =16
Vậy x=16
a,(72000+18000)-(3x+3000)=12000
90000-(3x+3000)=12000
3x+3000=90000-12000
3x+3000=78000
3x=78000-3000
3x=75000
x=75000:3
x=25000
b,[3.(x+2):7]:4=120
3.(x+2):7=120:4
3.(x+2):7=30
3.(x+2)=30.7
3.(x+2)=210
x+2=210:3
x+2=70
x=70-2
x=68
a) \(\left(x^2-9\right)\cdot\left(4^x-16\right)=0\)
\(\Rightarrow x^2-9=0\)hoặc \(4^x-16=0\)
\(x^2=9\) \(4^x=16\)
\(x^2=\left(\pm3\right)^2\) \(4^x=4^2\)
\(\Rightarrow x=\pm3\)hoặc \(x=2\)
b) \(5^x+5^{x+2}=650\)
\(\Rightarrow5^x+5^x\cdot25=650\)
\(\Rightarrow5^x\cdot\left(1+25\right)=650\)
\(\Rightarrow5^x\cdot26=650\)
\(\Rightarrow5^x=650\div26=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)Vậy \(x=2\)
c) \(2^{x+2}-2^x=96\)
\(2^x\cdot4-2^x=96\)
\(2^x\cdot\left(4-1\right)=96\)
\(2^x\cdot3=96\)
\(2^x=96\div3=32\)
\(2^x=2^5\)Vậy \(x=5\)
\(4\left(x+2\right)-8\left(x+3\right)=36\)
\(\Rightarrow4x+8-8x-24=36\)
\(\Rightarrow4x-8x=36+24-8\)
\(\Rightarrow-4x=52\)
\(\Rightarrow x=-13\)