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20+x=40+60
\(\Rightarrow\)20+x=100
\(\Rightarrow\)x=100-20
\(\Rightarrow\)x=80
10+90=40+x
\(\Rightarrow\)100=x+40
\(\Rightarrow\)x=100-40
\(\Rightarrow\)x=60
20 + x = 40 + 60
=> 20 + x = 100
=> x = 100 - 20
=> x = 80
10 + 90 = 40 + x
=> 100 = 40 + x
=> x = 100 - 40
=> x = 60
a)5+10=30-x
=>15=30-x
=>x=30-15
=>x=15
b)10+40=90-x
=>50=90-x
=>x=90-50
=>x=40
\(5+10=30-x\)
\(15=30-x\)
\(x=15\)
\(10+40=90-x\)
\(50=90-x\)
\(x=40\)
3x + 3x+2 = 90
3x + 3x.32 = 90
3x(1+32) = 90
3x.10 = 90
3x = 90 : 10
3x = 9
3x = 32
=>x = 2
a) 40 - x = 25
x = 40 - 25
x = 15
b) x - 1 = 10 + [ 90 - ( 17 - 8 ) 2 ]
x - 1 = 10 + [ 90 - 92 ]
x - 1 = 10 + [ 90 - 81 ]
x - 1 = 10 + 9
x - 1 = 19
x = 19 + 1
x = 20
\(\frac{x+10}{90}+\frac{x+20}{80}+\frac{x+30}{70}+\frac{x+40}{60}+\frac{x+50}{50}=-5\)
<=> \(\frac{x+10}{90}+1+\frac{x+20}{80}+1+\frac{x+30}{70}+1+\frac{x+40}{60}+1+\frac{x+50}{50}+1=0\)
<=> \(\frac{x+100}{90}+\frac{x+100}{80}+\frac{x+100}{70}+\frac{x+100}{60}+\frac{x+100}{50}=0\)
<=> \(\left(x+100\right)\left(\frac{1}{90}+\frac{1}{80}+\frac{1}{70}+\frac{1}{60}+\frac{1}{50}\right)=0\)
<=> x + 100 = 0
<=> x = -100
Vậy x = -100
1 6 − 2 5 < x 30 ≤ 1 2 − 8 15 ⇒ 5 30 − 12 30 < x 30 ≤ 15 30 − 16 30 ⇒ − 7 30 < x 30 ≤ − 1 30 ⇒ − 7 < x ≤ − 1 ⇒ x ∈ − 6 ; − 5 ; − 4 ; − 3 ; − 2 ; − 1
30 + x = 40 + 60
30 + x = 100
x = 100 - 30
x = 70
10 + 90 = 40 + x
100 = 40 + x
x = 100 - 40
x = 60
30+x=40+60
30+x=100
x=100-30
x=70
10+90=40+x
100 =40+x
100-40=x
60 =x