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a)\(\frac{5}{9}\times x-1=\frac{8}{9}\)
\(\frac{5}{9}\times x=\frac{8}{9}+1\)
\(\frac{5}{9}\times x=\frac{17}{9}\)
\(x=\frac{17}{9}:\frac{5}{9}\)
\(x=\frac{17}{5}\)
Ta có : (x + 2) + (x + 5) + (x + 8) + ...... + (x + 32) = 198
<=> (x + x + x + ...... + x) + (2 + 5 + 8 + ....... + 32) = 198
<=> 11x + 187 = 198
=> 11x = 198 - 187
=> 11x = 11
=> x = 1
x+x*\(\frac{1}{2}\):\(\frac{2}{9}\)+x:\(\frac{2}{7}\)=252
x+x*\(\frac{9}{4}\)+x*\(\frac{7}{2}\)=252
x*(1+\(\frac{9}{4}\)+\(\frac{7}{2}\))=252
x*\(\frac{27}{4}\)=252
x=252:\(\frac{27}{4}\)
x=\(\frac{112}{3}\)
Vậy x=\(\frac{112}{3}\)
Học tốt
\(x+x\times\frac{1}{2}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(x\times1+x\times\frac{9}{4}+x\times\frac{7}{2}=252\)
\(x\times\left(1+\frac{9}{4}+\frac{7}{2}\right)=252\)
\(x\times\frac{17}{4}=252\)
\(x=252\div\frac{17}{4}\)
\(x=252\times\frac{4}{17}\)
\(x=\frac{1008}{17}\)
Chắc sai =]]
\(x+x×\frac{1}{3}:\frac{2}{9}+x×\frac{2}{7}=252\)
\(\Rightarrow x+x×\frac{1}{3}×\frac{9}{2}+x×\frac{7}{2}=252\)
\(x\left(1+\frac{1}{3}×\frac{9}{2}+\frac{7}{2}\right)=252\)
\(x×\frac{36}{6}=252\)
\(x×6=252\)
\(x=252:6\)
\(x=43\)
\(x+x\times\frac{1}{3}\div\frac{2}{9}+x\div\frac{2}{7}=252\)
\(\Leftrightarrow x+x\times\frac{1}{3}\times\frac{9}{2}+x\times\frac{7}{2}=252\)
\(\Leftrightarrow x\left(1+\frac{1}{3}\times\frac{9}{2}+\frac{7}{2}\right)=252\)
\(\Leftrightarrow x\left(\frac{6}{6}+\frac{9}{6}+\frac{21}{6}\right)=252\)
\(\Leftrightarrow x\times\frac{36}{6}=252\)
\(\Leftrightarrow x\times6=252\)
\(\Leftrightarrow x=252\div6\)
\(\Leftrightarrow x=43\)
\(\Leftrightarrow x+1,5x+3,5x=252\)
<=>6x=252
<=>x=42
ủng hộ nhe
y+y x 1/3 : 2/9 + y :2/7 = 252
y x 1 + y x (1/3 x 9/2 ) + y x 7/2 = 252
y x 1/1 + y x 3/2 + y x 7/2 = 252
y x (1/1 + 3/2 + 7/2 ) = 252
y x 6 = 252
y = 252 : 6
y = 42