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a, ( 152 +và 2/4 - 148 và 3/8 ) : 0,2 = x : 0,3
=> 33/8 : 1/5 = x : 3/10
=> x : 3/10 = 165/8
=> x = 99/10
b, ( 85 và 7/30 - 83 và 5/18 ) : 2 và 2/3 = 0,01x : 4
=> 88/45 : 8/3 = 0,01x : 4
=> 0,01x : 4 = 11/15
=> 0,01x = 44/15
=> x = 880/3
c, x - 1/ x + 5 = 6/7
=> 7( x - 1 ) = 6( x + 5 )
=> 7x - 7 = 6x + 30
=> 7x - 6x = 7 + 30
=> x = 37
d, x2/6 = 24/25
=> x2. 25 = 6 . 24
=> x2.25 = 144
=> x2 = 144/25
=> x = ( 12/5)2 hoặc x = ( -12/5)
g, x - 3/ x + 5 = 5/7
=> 7( x - 3 ) = 5 ( x + 5 )
=> 7x - 21 = 5x + 25
=> 7x - 5x = 21 + 25
=> 2x = 46
=> x = 23
1) a) Ta có: \(\frac{x}{-15}=\frac{-60}{x}\) \(\Rightarrow x^2=\left(-15\right).\left(-60\right)=900\)
\(\Rightarrow x=30\)
b) \(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\) \(\Rightarrow x.\left(-x\right)=\left(-2\right).\frac{8}{25}\)
\(\Rightarrow x.\left(-x\right)=\frac{-16}{25}\)
\(\Rightarrow x.\left(-x\right)=\left(\frac{-4}{5}\right).\frac{4}{5}\)
Vậy \(x=\frac{4}{5}\)
2) a) \(3,8: \left(2x\right)=\frac{1}{4}:2\frac{2}{3}\)
\(\Rightarrow3,8: \left(2x\right)=\frac{3}{32}\)
\(\Rightarrow2x=\frac{3}{32}:3,8=\frac{15}{608}\)
\(x=\frac{15}{608}:2=\frac{15}{1216}\)
Vậy \(x=\frac{15}{1216}\)
b) \(\left(0,25x\right):3=\frac{5}{6}:0,125\)
\(\Rightarrow\left(0,25x\right):3=\frac{20}{3}\)
\(\Rightarrow0,25x=\frac{20}{3}.3=20\)
\(\Rightarrow x=20:0,25=80\)
Vậy x = 80
c) \(0,01:2,5=\left(0,75x\right):0,75\)
\(\Rightarrow\frac{1}{250}=\left(0,75x\right):0,75\)
\(\Leftrightarrow0,75x=\frac{1}{250}.0,75=\frac{3}{1000}\)
\(\Rightarrow x=\frac{3}{1000}:0,75=\frac{1}{250}\)
Vậy \(x=\frac{1}{250}\)
d) \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1x\right)\)
\(\Rightarrow\frac{5}{3}=\frac{2}{3}:\left(0,1x\right)\)
\(\Rightarrow0,1x=\frac{5}{3}.\frac{2}{3}=\frac{10}{9}\)
\(\Rightarrow x=\frac{10}{9}:0,1=\frac{100}{9}\)
Vậy \(x=\frac{100}{9}\)
a) \(\frac{x}{-15}=\frac{-60}{x}\Leftrightarrow x.x=-15.\left(-60\right)\Leftrightarrow x^2=900\Leftrightarrow x^2=\orbr{\begin{cases}30^2\\\left(-30\right)^2\end{cases}}\Leftrightarrow x=\orbr{\begin{cases}30\\-30\end{cases}}\)
\(\left|x+\frac{1}{2}\right|+\left|y-\frac{3}{4}\right|+\left|z-1\right|=0\) \(0\)
<=> \(\hept{\begin{cases}x+\frac{1}{2}=0\\y-\frac{3}{4}=0\\z-1=0\end{cases}}\)
<=> \(\hept{\begin{cases}x=-\frac{1}{2}\\y=\frac{3}{4}\\z=1\end{cases}}\)
\(\left|x-\frac{3}{4}\right|+\left|\frac{2}{5}-y\right|+\left|x-y+z\right|=0\)
<=> \(\hept{\begin{cases}x-\frac{3}{4}=0\\\frac{2}{5}-y=0\\x-y+z=0\end{cases}}\)
<=>\(\hept{\begin{cases}x=\frac{3}{4}\\y=\frac{2}{5}\\\frac{3}{4}-\frac{2}{5}+z=0\end{cases}}\)
<=> \(\hept{\begin{cases}x=\frac{3}{4}\\y=\frac{2}{5}\\z=\frac{-7}{20}\end{cases}}\)
\(\left|x-\frac{2}{3}\right|+\left|x+y+\frac{3}{4}\right|+\left|y-z-\frac{5}{6}\right|=0\)
<=> \(\hept{\begin{cases}x-\frac{2}{3}=0\\x+y+\frac{3}{4}=0\\y-z-\frac{5}{6}=0\end{cases}}\)
<=> \(\hept{\begin{cases}x=\frac{2}{3}\\y=\frac{-17}{12}\\z=\frac{-9}{4}\end{cases}}\)
\(\left|x-\frac{1}{2}\right|+\left|xy-\frac{3}{4}\right|+\left|2x-3y-z\right|=0\)
<=> \(\hept{\begin{cases}x-\frac{1}{2}=0\\xy-\frac{3}{4}=0\\2x-3y-z=0\end{cases}}\)
<=> \(\hept{\begin{cases}x=\frac{1}{2}\\y=\frac{3}{4}:\frac{1}{2}=\frac{3}{2}\\z=\frac{-7}{2}\end{cases}}\)
các câu còn lại tương tự
a) \(\frac{x-1}{x+5}=\frac{6}{7}\)
\(\Rightarrow7.\left(x-1\right)=6.\left(x+5\right)\)
\(\Rightarrow7x-7=6x+30\)
\(\Rightarrow7x-6x=7+30\)
\(\Rightarrow x=37\)
b) \(\frac{x^2}{6}=\frac{24}{25}\)
\(\Rightarrow25.x^2=24.6\)
\(\Rightarrow25.x^2=144\)
\(\Rightarrow x^2=144:25\)
\(\Rightarrow x^2=\frac{144}{25}\)
\(\Rightarrow x^2=\frac{12^2}{5^2}\)
\(\Rightarrow x^2=\frac{12}{5}^2\)
\(\Rightarrow x=\pm\frac{12}{5}\)
\(c,\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
\(\Leftrightarrow(x-2)(x+7)=(x+4)(x-1)\)
\(\Leftrightarrow x^2+5x-14=x^2+3x-4\)
\(\Leftrightarrow x^2+5x-14-x^2+3x=-4\)
\(\Leftrightarrow\left[x^2-x^2\right]+5x-3x-14=-4\)
\(\Leftrightarrow2x-14=-4\)
\(\Leftrightarrow2x=10\Leftrightarrow x=5\)
1. Đổi về tỉ số của hai sô nguyên:
a)\(\frac{0,125}{0,625}=\frac{1}{5}\)
b)\(\frac{3\frac{1}{2}}{0,25}=14\)
c)\(\frac{\frac{9}{2}}{2\frac{5}{6}}=\frac{27}{17}\) (ko biết đề đúng ko)
2. Tìm x, biết:
a)\(\frac{-10}{x}=\frac{x}{3}\)
\(\Rightarrow x^2=\left(-10\right).3\)
\(x^2=-30\)
\(x=-\sqrt{30}\)
b)\(\frac{x+1}{7}=\frac{2-x}{3}\)
\(\Rightarrow3.\left(x+1\right)=7.\left(2-x\right)\)
\(3x+3=14-7x\)
\(3x+7x=14-3\)
\(10x=11\)
\(\Rightarrow x=1.1\)
c)\(\frac{5}{2}=\frac{x+2}{x-3}\)
\(\Rightarrow5.\left(x-3\right)=2.\left(x+2\right)\)
\(5x-15=2x+4\)
\(5x-2x=4+15\)
\(3x=19\)
\(\Rightarrow x=\frac{19}{3}\)
d)\(\frac{x}{x+1}=\frac{2x}{2x-3}\)
\(\Rightarrow\)\(\frac{x}{x+1}-\frac{2x}{2x-3}=0\)
Đến đây bí quá chịu TO BE CONTINUED
