Question

[My Nguyễn Thảo]

Tìm x thuộc z

1/2-(1/3+1/4)<x<1/48-(1/16-1/6)

ai làm nhanh và đúng nhất mk tick cho!!!!!

Answer 1

[๖ۣۜღLê Phi Hùng๖ۣۜღ]

Gỉai

\(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)\)<x<\(\dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)

\(\Leftrightarrow\dfrac{6}{12}-\dfrac{4}{12}-\dfrac{3}{12}\)<x<\(\dfrac{1}{48}-\dfrac{3}{48}+\dfrac{8}{48}\)

\(\Leftrightarrow-\dfrac{1}{12}\)<x<\(\dfrac{2}{16}\)\(\Leftrightarrow\dfrac{4}{48}< x< \dfrac{6}{48}\)

\(x\in\left\{\dfrac{4}{48}< x< \dfrac{6}{48}\right\}\)

Answer 2

[DTD2006ok]

\(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)

=> \(\frac{1}{2}-\frac{7}{12}< x< \frac{1}{48}-\frac{-5}{48}\)

=> \(\frac{-1}{12}< x< \frac{6}{48}=>\frac{-1}{12}< x< \frac{1}{8}\)

=> \(\frac{-1}{12}< x< \frac{1}{8}\)