Question

[doan nhut huy]

Tìm x để \(\frac{37}{42}=\frac{41-x}{32}\)

Answer 1

[Trần Thị Loan]

Quy đồng \(\frac{37}{42}=\frac{37\times32}{42\times32}=\frac{1184}{1344};\frac{41-x}{32}=\frac{42\times\left(41-x\right)}{42\times32}=\frac{42\times\left(41-x\right)}{1344}\)

\(\frac{37}{42}=\frac{41-x}{32}\) nên  \(\frac{1184}{1344}=\frac{42\times\left(41-x\right)}{1344}\)

=>   42 x (41 - \(x\)) = 1184

    42 x 41 - 42 x \(x\) = 1184

    1722 - 42 x \(x\) = 1184

   42 x \(x\) = 1722 - 1184 

   42 x \(x\) = 538 

   \(x\) = 538 / 42 =  269 / 21