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\(3\frac{1}{5}x+125x=178\)
=> 3,2x + 125x = 178
=> 128,2x = 178
\(\Rightarrow x=\frac{890}{641}\)
\(3\frac{1}{5}x+125x=178 \)
\(\frac{16}{5}x+125x=178\)
\(x.\left(\frac{16}{5}+125\right)=178\)
\(x.\frac{641}{5}=178\)
\(x=178:\frac{641}{5}\)
\(x=\frac{890}{641}\)
vậy \(x=\frac{890}{641}\)
Ta có:+ x/16=5/8
Suy ra: x.8=5.16
x.8=80
x=10
+-15/y=5/8
suy ra: -15.8=y.5
-120=y.5
-24=y
Vậy x=10 , y=-24
\(1\frac{3}{5}+\left(\frac{\frac{2}{7}+\frac{2}{17}+\frac{2}{37}}{\frac{5}{7}+\frac{5}{17}+\frac{5}{37}}\right)x=\frac{16}{5}\)
\(\Rightarrow\frac{2\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}{5\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}.x=\frac{16}{5}-\frac{8}{5}\)
\(\Rightarrow\frac{2}{5}.x=\frac{8}{5}\)
\(\Rightarrow x=\frac{8}{5}:\frac{2}{5}=4\)
vậy x=4
\(\frac{7}{5}+\left(\frac{2\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}{5\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}\right)\cdot x=\frac{16}{5}\)
\(\frac{2}{5}x=\frac{16}{5}-\frac{7}{5}\)
\(\frac{2}{5}x=\frac{9}{5}\)
x = \(\frac{9}{5}:\frac{2}{5}\)
x = 9/2
\(1\frac{2}{5}+\left(\frac{\frac{2}{7}+\frac{2}{17}+\frac{2}{37}}{\frac{5}{7}+\frac{5}{17}+\frac{5}{37}}\right).x=\frac{16}{5}\)
\(\frac{7}{5}+\left[\frac{2.\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}{5.\left(\frac{1}{7}+\frac{1}{17}+\frac{1}{37}\right)}\right].x=\frac{16}{5}\)
\(\frac{7}{5}+\frac{2}{5}.x=\frac{16}{5}\)
\(\frac{2}{5}.x=\frac{16}{5}-\frac{7}{5}\)
\(\frac{2}{5}.x=\frac{9}{5}\)
\(x=\frac{9}{5}:\frac{2}{5}\)
\(x=\frac{9}{5}.\frac{5}{2}\)
\(x=\frac{9}{2}\)
=.8/5+((2*17*37+2*7*37+2*7*17)/(7*17*37))/((5*17*37+5*7*37+5*7*17)/(7*17*37))*x=16/5
=>8/5+((2*17*37+2*7*37+2*7*17)/(7*17*37))*((7*17*37)/(5*17*37+5*7*37+5*7*17))*x=16/5
=>8/5+(2(17*37+7*37+7*17))/(5(17*37+7*37+7*17))*x=16/5
=>8/5+(2/5)*x=16/5
=>(2/5)*x=16/5-8/5
=>(2/5)*x=8/5
=>x=(8/5)/(2/5)
=>x=4
Vậy x=4
Theo t/c dãy tỉ số bằng nhau :
\(\frac{x}{5}=\frac{y}{3}=\frac{x+y}{3+5}=\frac{16}{8}=2\)
\(\Rightarrow x=10\)
\(y=6\)
Ta cos\(\frac{16}{5}x=178-125x\)
=> \(\frac{16}{5}x+125x=178\)
=> \(x\left(\frac{16}{5}+125\right)=178\)
=> \(x.128,2=178\)
=> x = \(\frac{890}{641}\)