Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)
a) x-3/4=2x+1/2
=>x-2x=3/4+1/2
=>-x=5/4
=>x=-5/4(nhân cả 2 về với -1)
b)3.(x-2) - 2. (x+3)=4
3x-6-2x-6=4
x-12=4
x=16
c)/x-3/2/ -1/2=-35 . (1/3)^6
/x-3/2/-1/2=-35.1/36
/x-3/2/-1/2=-1/3
/x-3/2/=-1/3+1/2
/x-3/2/=1/6
TH1:x-3/2=1/6=>x=5/3
TH2:x-3/2=-1/6=>x=4/3
/x
/x-3/2/
a) \(x-\frac{3}{4}=2x+\frac{1}{2}\)
\(x-2x=\frac{1}{2}+\frac{3}{4}\)
\(-x=\frac{5}{4}\)
\(x=-\frac{5}{4}\)
a ) 4 1 2 − x = − 3 2 3 ⇒ x = 4 1 2 + 3 2 3 = 9 2 + 11 3 = 8 1 6 .
b ) x − 2 2 3 = 3 1 3 ⇒ x = 2 2 3 + 3 1 3 = 6